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inysia [295]
3 years ago
7

PLEASE! :( Two aqueous solutions of AgNO3 and NaCl are mixed. Which of the following diagrams best represents the mixture? For s

implicity, water molecules are not shown (Ag + = gray, Cl- = orange, Na + = green, NO ^ - 3 = blue) PLEASE I NEED HELP I ONLY HAVE 15 MINS PLS :'((​

Chemistry
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

NaCl + Ag(NO₃) --> Na(NO₃) + AgCl

Explanation:

Chemical equation:

NaCl + Ag(NO₃) --> Na(NO₃) + AgCl

The given reaction represent the double displacement reaction. Anion and cation of both reactant exchange with each others.

The anion of sodium chloride(Cl⁻) combine with cation of silver nitrate Ag⁺ and  NO₃⁻ combine with Na⁺.

The third equation is correct while others are in correct.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

SORRY CAUSE IDK IF THAT HELPED :(

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What is pH when 4.0 mL of 2.0 M barium hydroxide is added to 10.0 mL of 1.00 M nitric acid?
Anika [276]

Answer : The pH of the solution will be 13.63.

Solution:

Moles of hydroxide ions in barium hydroxide solution

BaOH_2\rightarrow Ba^++2(OH)^-

Number of moles = (concentration)\times(volume in liters) ...(1)(1L=1000mL)

<em>2.0 M barium hydroxide in solution</em>

Number of moles of Ba(OH)_2 in 2.0 M solution=2.0 M\times 0.004 L=0.008 moles

If One mole of barium hydroxide gives two moles of hydroxide in solution then 0.008 moles will give:

Number of moles of  OH^-=(2)\times (0.008 mol)=0.016 moles

Moles of H^+ ions in nitric acid

HNO_3\rightarrow NO^{-}_{3}+H^+

<em>In 1.00 M nitric acid solution</em>

Moles of nitric acid in 1.0 M solution =(1.0 M)\times(0.010 L)=0.010 moles

If one mole of nitric acid will give one moles of H^+ ion.

Then 0.010 moles of nitric acid in solution will give :

Number of moles of  H^+=(1)\times (0.010 mol)=0.010 moles

Since , the reaction will be neutralization reaction, equal number of moles of H^+ will neutralize equal number of moles of OH^-

So,0.010 moles of H^+ will neutralize 0.010 moles of OH^- in the solution

Remaining moles of OH^-=0.016- 0.01=0.006 moles

Concentration of [OH^-] resulting solution

Resulting volume of the solution : 0.004 + 0.010 liters

Calculating [OH^-] by using equation (1).

[OH^-]=\frac{0.006}{0.004L+0.010 L}=0.4285 M

pOH=-log[OH^-]=-log(0.4285)=0.367

pH=14-pOH=14-0.367=13.633

The pH of the solution will be 13.633.

8 0
4 years ago
How much (in mL) 12.1 M solution of hydrochloric acid would be required to make 500 mL of a 2.5 M solution
victus00 [196]

Answer:

Volume of the concentrated solution, which is needed is 103.30 mL

Explanation:

Let's apply the formula for dilutions to solve the problem

Conc. Molarity . Conc. volume = Dil. Molarity . Dil volume

12.1 M . Conc. volume = 2.5 M . 500 mL

Conc. volume = (2.5 M . 500 mL) / 12.1M

Conc. volume = 103.30 mL

6 0
4 years ago
What group of substances does this substance belong to?
HACTEHA [7]
In comparison see it is very easy in goolge
4 0
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Which pair of elements has atoms with the same number of valence electrons ?
RoseWind [281]

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Explanation:

3 0
3 years ago
A one or two letter abbreviation for a chemical element. True or false
Feliz [49]

Answer:

True

Explanation:

All the chemical elements have their abbreviations as one or two letters

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Majority of abbreviations are based on their english names

3 0
3 years ago
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