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inysia [295]
3 years ago
7

PLEASE! :( Two aqueous solutions of AgNO3 and NaCl are mixed. Which of the following diagrams best represents the mixture? For s

implicity, water molecules are not shown (Ag + = gray, Cl- = orange, Na + = green, NO ^ - 3 = blue) PLEASE I NEED HELP I ONLY HAVE 15 MINS PLS :'((​

Chemistry
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

NaCl + Ag(NO₃) --> Na(NO₃) + AgCl

Explanation:

Chemical equation:

NaCl + Ag(NO₃) --> Na(NO₃) + AgCl

The given reaction represent the double displacement reaction. Anion and cation of both reactant exchange with each others.

The anion of sodium chloride(Cl⁻) combine with cation of silver nitrate Ag⁺ and  NO₃⁻ combine with Na⁺.

The third equation is correct while others are in correct.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

SORRY CAUSE IDK IF THAT HELPED :(

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Matter that has a uniform and definite composition is called a vapor
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Lithium reacts with bromine
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2Li + Br2 → 2LiBr
Lithium react with bromine to produce lithium bromide. The reaction proceeds at room temperature.
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3 years ago
What volume of a 0.580-m solution of cacl2 contains 1.28 g solute?
goldfiish [28.3K]

Answer : 19.9 mL


Explanation : We have the moles of Calcium chloride and the weight of it as 1.28 g,


Here, molarity has to be related with the volume so, 0.580 M = 0.580 mol/L


so now in 1.28 g there will be : 1.28 X (1 g / 111 mol of calcium chloride) = 0.01153 mol


Now, we can find out the volume from this;


0.01153 mol X (1 L / 0.580 mol) X (1000 mL / 1 L) = 19.9 mL


Hence, the volume will be 19.9 mL


7 0
3 years ago
one method for generating chlorine gas is by reacting potassium permanganate and hydrochloric acid. how many liters of Cl2 at 40
Ronch [10]

<u>Answer:</u> The volume of chlorine gas produced in the reaction is 2.06 L.

<u>Explanation:</u>

  • <u>For potassium permanganate:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of potassium permanganate = 6.23 g

Molar mass of potassium permanganate = 158.034 g/mol

Putting values in above equation, we get:

\text{Moles of potassium permanganate}=\frac{6.23g}{158.034g/mol}=0.039mol

  • <u>For hydrochloric acid:</u>

To calculate the moles of hydrochloric acid, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of HCl = 6.00 M

Volume of HCl = 45.0 mL = 0.045 L   (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

6.00mol/L=\frac{\text{Moles of HCl}}{0.045L}\\\\\text{Moles of HCl}=0.27mol

  • For the reaction of potassium permanganate and hydrochloric acid, the equation follows:

2KMnO_4+16HCl\rightarrow 2MnCl_2+5Cl_2+2KCl+8H_2O

By Stoichiometry of the reaction:

16 moles of hydrochloric acid reacts with 2 moles of potassium permanganate.

So, 0.27 moles of hydrochloric acid will react with = \frac{2}{16}\times 0.27=0.033moles of potassium permanganate.

As, given amount of potassium permanganate is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

16 moles of hydrochloric acid reacts with 5 moles of chlorine gas.

So, 0.27 moles of hydrochloric acid will react with = \frac{5}{16}\times 0.27=0.0843moles of chlorine gas.

  • To calculate the volume of gas, we use the equation given by ideal gas equation:

PV=nRT

where,

P = pressure of the gas = 1.05 atm

V = Volume of gas = ? L

n = Number of moles = 0.0843 mol

R = Gas constant = 0.0820\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 40^oC=[40+273]K=313K

Putting values in above equation, we get:

1.05atm\times V=0.0843\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 313K\\\\V=2.06L

Hence, the volume of chlorine gas produced in the reaction is 2.06 L.

3 0
4 years ago
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