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Nastasia [14]
3 years ago
12

Solid cadmium sulfide reacts with an aqueous solution of sulfuric acid . Express your answer as a balanced chemical equation. Id

entify all of the phases in your answer. nothing
Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Explanation:

When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

          CdS(s) + H_{2}SO_{4}(aq) \rightarrow CdSO_{4}(aq) + H_{2}S(g)

Hence, ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) + SO^{2-}_{4}(aq) \rightarrow Cd^{2+}(aq) + SO^{2-}_{4}(aq) + H_{2}S(g)

Therefore, net ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)

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Answer:

H^+(aq) + OH^-(aq) —> H2O(l)

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Ca(OH)2 is a strong base and will dissociates as follow:

Ca(OH)2(aq) —> Ca^2+(aq) + 2OH^-(aq)

HCl is a strong acid and will dissociates as follow:

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Thus, In solution a double displacement reaction occurs as shown below:

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To get the net ionic equation, cancel out Ca^2+ and 2Cl^-

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If an atom has 13 electrons how many electron shells does it have
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