3 years ago

Whats A and B How do i solve this ?

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

4 0

Answer:

$\begin{pmatrix}-2\\-4\end{pmatrix}$

Step-by-step explanation:

The question is, how many x and y steps do I have to move the P picture to get it in the Q position. The answer is 2 to the left, so -2, and 4 down, so -4.

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Write the equation in standard form. Identity the center and radius. x² + y2 + 8x-4y-7=0

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Answer:

equation;

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Radius is

$3 \sqrt{3}$

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

$(x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$

Where (h,k) is center

r is the radius

So first we group like Terms together

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${x}^{2} + 8x + {y}^{2} - 4y = 7$

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Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

$(\frac{8}{2} ) {}^{2} = 16$

and

$( - \frac{4}{2} ) {}^{2} = 4$

so we have

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 7 + 16 + 4$

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 27$

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

$\sqrt{27} = 3 \sqrt{3}$

So the radius is 3 times sqr root of 3.

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