First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
Answer:
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Step-by-step explanation:
Answer:
Substitute 0 for y
and solve to find the x-intercept.
x-intercept(s): (6,0)
Answer:
50%
Step-by-step explanation:
30+10=40
40+20=60
120-60=60
60 is 50% of 120
Hi, I am very happy to help you! I know how to do this! Super Easy!!!!
You will have 2 different x's and they are 3 and 6.
You will have 2 different y's and they are 16 and 19.
In order to get m, you have to subtract y2-y1/x2-x1=m
So the answer would be 1.
In order to solve b, you have to choose one of your given coordinate points and plug them in for x and y and plug in your m, which is 1.
I will be choosing the coordinate points (3,16)
So our b is 13.
So our answer using the form is y=1x+13