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cluponka [151]
3 years ago
14

PLEASE HELP!!! 20 POINTS!!!!

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0
To evaluate the expression all you have to do is substitute the value for the variable.

3 + y + 6, y = 5
3 + 5 + 6
8 + 6
14.

The solution is 14.
rewona [7]3 years ago
3 0
The solution is 14, because 3+5+6=14
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Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of
Tanzania [10]

Answer:

4.0541

Step-by-step explanation:

I don't know if this is correct but this is what I got.

You would take the error and divide it by the theoretical value and then multiply that by 100.

7.7 - 7.4 = 0.3

0.3 ÷ 7.4 = 0.04054054

0.04054054 x 100 = 4.05405405 (simplify) = 4.0541%

Hope I helped in any way

8 0
2 years ago
Conjunction and disconjuction​
maks197457 [2]

Step-by-step explanation:

When two statements are connected with an 'and,' you have a conjunction.

For conjunctions, both statements must be true for the compound statement to be true.

When the connector between two statements is "or," you have a disjunction. In this case, only one statement in the compound statement needs to be true for the entire compound statement to be true.

7 0
2 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
3 years ago
Read 2 more answers
Please solve this for me i dont understand and i will be very appreciative
vredina [299]

Answer: b is for ░▒▓█ Ř █▓▒░

Step-by-step explanation:

5 0
3 years ago
I need help with this (write an inequality)​
kipiarov [429]

Answer:

A.)x-9>20

B.) x-7>12

C.) 8×y>16

D.) y÷7 ≤-5

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3 years ago
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