Answer:
the magnitude of the velocity of one particle relative to the other is 0.9988c
Explanation:
Given the data in the question;
Velocities of the two particles = 0.9520c
Using Lorentz transformation
Let relative velocity be W, so
v
= ( u + v ) / ( 1 + ( uv / c²) )
since each particle travels with the same speed,
u = v
so
v
= ( u + u ) / ( 1 + ( u×u / c²) )
v
= 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )
we substitute
v
= 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )
v
= 1.904c / ( 1 + 0.906304 )
v
= 1.904c / 1.906304
v
= 0.9988c
Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c
Answer:
refractive index for water,glass,diamond are 0.752m, 0.667m, 0.413m respectively
Explanation:
refractive index (n) = 
velocity =
The time for travel is kept constant for all mediums.
refractive index (n) = 
distance in medium = 

For water, n= 1.33


For glass, n=1.5


For diamond, n= 2.42


Answer:
increasing; speeding up is my answer
Answer:
a)
, b)
, c) 
Explanation:
a) The change in the gravitational potential energy of the marble-Earth system is:


b) The change in the elastic potential energy of the spring is equal to the change in the gravitational potential energy, then:

c) The spring constant of the gun is:



