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3 years ago

___are pictures of relationship

Physics

1 answer:

TiliK225 [7]3 years ago

8 0

-- selfies with both people in it

-- wedding photos

-- boy-and-his-dog snapshots

-- some graphs

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Which of the following is defined as a force that pushes and pulls the current through the circuit? Group of answer choices D) r

Oksi-84 [34.3K]

Answer:

C voltage

Explanation:

Voltage is the change in electric potential so basically current flows from high potential to low potential due to voltage.

5 0

3 years ago

Waves are observed passing under a dock. Wave crests are 8.0 meters apart. The time for a complete wave to pass by

lara31 [8.8K]

Answer:

Option D

2 m/s

Explanation:

The speed is given by distance/time

The complete wave has a distance of 8 m (This is the wavelength)

Time taken for complete wave is 4 s

Therefore, velocity= 8 m/ 4 s= 2 m/s

The amplitude is the distance between crest and trough hence 9 m- 6 m= 3 m

Frequency is 1/period and in this case period is 4 s hence frequency= 1/4= 0.25 Hz

Essentially, what we wanted is velocity

3 0

4 years ago

I'll give 20 points!!!

qwelly [4]

Answer:

Its b)

Explanation:

4 0

3 years ago

If you increase the frequency of a sound wave four times, what will happen to its speed?

ozzi

The speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

<h3>How to calculate the frequency of a wave.</h3>

Mathematically, the frequency of a sound wave is given by this formula:

$F = \frac{V}{\lambda}$

<u>Where:</u>

F is the frequency of a sound wave.

V is the velocity of a sound wave.

$\lambda$ is the wavelength of a sound wave.

<u>Note:</u> The frequency of the sound wave is increased four (4) times.

F = 4F

Substituting the given parameters into the formula, we have;

$4F = \frac{V}{\lambda}\\\\V=4F\lambda$

Therefore, the speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

Read more on sound wave here: brainly.com/question/19250621

4 0

3 years ago

A concave mirror produces a real image that is three times as large as the object. If the object is 20 cm in front of the mirror

TiliK225 [7]

Answer:

The image is produced 60 cm behind the mirror

The focal length of the mirror is 30 cm

Explanation:

u = Object distance = 20 cm

v = Image distance

f = Focal length

m = Magnification = 3

$m=-\frac{v}{u}\\\Rightarrow 3=-\frac{v}{20}\\\Rightarrow v=-3\times 20\\\Rightarrow v=-60\ cm$

The image is produced 60 cm behind the mirror

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{20}+\frac{1}{-60}\\\Rightarrow \frac{1}{f}=\frac{1}{30}\\\Rightarrow f=\frac{30}{1}=30\ cm$

The focal length of the mirror is 30 cm

8 0

3 years ago