A man ties one end of a strong rope 8.17 m long to the bumper of his truck, 0.524 m from the ground, and the other end to a vert
ical tree trunk at a height of 2.99 m. He uses the truck to create a tension of 8.57 102 N in the rope. Compute the magnitude of the torque on the tree due to the tension in the rope, with the base of the tree acting as the reference point.
1 answer:
Answer:
2442.5 Nm
Explanation:
Tension, T = 8.57 x 10^2 N
length of rope, l = 8.17 m
y = 0.524 m
h = 2.99 m
According to diagram
Sin θ = (2.99 - 0.524) / 8.17
Sin θ = 0.3018
θ = 17.6°
So, torque about the base of the tree is
Torque = T x Cos θ x 2.99
Torque = 8.57 x 100 x Cos 17.6° x 2.99
Torque = 2442.5 Nm
thus, the torque is 2442.5 Nm.
You might be interested in
Answer:
Work done, W = 3.78 Joules
Explanation:
It is given that,
Displacement in x-y coordinate,
Magnitude of force, F = 1.3 N
The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.
Firstly, finding the vector form of force as :
The work done is given by :
W = 3.78 Joules
So, the work done by the force is 3.78 Joules. Hence, this is the required solution.