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Lisa [10]
3 years ago
5

What is the area????

Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

49.1 cm^2

Step-by-step explanation:

The appropriate area formula is ...

area = (1/2)(side 1)(side 2)(sin(angle between))

= (1/2)(10 cm)(12 cm)·sin(55°) = 60·sin(55°) cm^2

area ≈ 49.1 cm^2

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Give brainliest! Right triangle ABC is on a coordinate plane. Segment AB is on the line y = 2 and is 3 units long. Point C is on
Anastasy [175]

Answer: y coordinate is 6

Step-by-step explanation:

6=1/2(3)(h)

If you solve for H then

h=4

So, add 4 to the line y=2

y=2+4

2+4= 6

Hence, the possible y coordinate of point C is 6

Hope this helped!

I would really appreciate if marked brainlest !

Thank you !

6 0
3 years ago
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Please help me with this question
marshall27 [118]

Answer:

80,

Step-by-step explanation:

the way to find the volume of a prism is the following, get 3 measurements, the length, the width and the height (in this case you already have all 3) so simply multiply they together(2*5*8=80)

6 0
3 years ago
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A cylindrical metal tin has a diameter of 12 inches and a height of 4 inches.
Tanya [424]

Answer:

452.39

Step-by-step explanation:

5 0
3 years ago
Plz tell me how to do question 18
bagirrra123 [75]

Answer:

750kmph

Step-by-step explanation:

Average is sum of all parts divided by the number of parts.

Let Stot be average speed for total trip (800kmph).

Let S1 be speed for first quarter of trip (950kmph).

Let S2, S3, and S4 be the speeds of each of the remaining quarters respectively.

Let Sans be the average speed for the remaining three quarters of the trip (a.k.a. The Answer!).

Stot = (S1 + S2 + S3 + S4) / 4

800kmph = (950kmph + S2 + S3 + S4) / 4

3200kmph = 950kmph + S2 + S3 + S4

3200kmph - 950kmph = 2250kmph = S2 + S3 + S4

Divide both sides by 3.

2250kmph / 3 = (S2 + S3 + S4) / 3 = Sans

Sans = 750kmph

8 0
3 years ago
I am having trouble understanding the concept of completing the square in math. Could someone please assist me on how to do so?
enyata [817]
"Completing the square" is the process used to derive the quadratic  formula for the general quadratic ax^2+bx+c=0.  Suppose you did not know the value of a,b, or c of the quadratic...

ax^2+bx+c=0  You need a leading coefficient of one for the process to work, so you divide the whole equation by a

x^2+bx/a+c/a=0  now you move the constant to the other side of the equation

x^2+bx/a=-c/a  now you halve the linear coefficient, square that, then add that value to both sides, ie, (b/(2a))^2=b^2/(4a^2)...

x^2+bx/a+b^2/(4a^2)=b^2/(4a^2)-c/a  now the left side is a perfect square...

(x+b/(2a))^2=(b^2-4ac)/(4a^2)  now take the square root of both sides

x+b/(2a)=±√(b^2-4ac)/(2a)  now subtract b/(2a) from both sides

x=(-b±√(b^2-4ac))/(2a)

It is actually much simpler keeping track of everything when using known values for a,b, and c, but the above explains the actual process used to create the quadratic formula, which the above solution is. :)
8 0
4 years ago
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