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emmainna [20.7K]
3 years ago
9

Farmer Ed has 950 meters of​ fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fen

ce the side along the​ river, find the length and width of the plot that will maximize the area. What is the largest area that can be​ enclosed?
Mathematics
1 answer:
natulia [17]3 years ago
6 0

The perimeter for this case is given by:

P = y + 2x

Substituting values we have:

y + 2x = 950

The area is given by:

A = x * y

Writing the area based on a variable we have:

A (x) = x * (950 - 2x)\\A (x) = -2x ^ 2 + 950x

We derive the area to obtain the maximum of the function:

A '(x) = -4x + 950

We equal zero and clear x:

-4x + 950 = 0\\4x = 950\\x = 950/4\\x = 237.5

Then, the other dimension is given by:

y = 950 - 2x\\y = 950 - 2 * (237.5)\\y = 475

Finally the maximum area is:

A = (237.5) * (475)\\A = 112812.5 m ^ 2

Answer:

The length and width of the plot that will maximize the area are:

x = 237.5 m\\y = 475 m

The largest area that can be enclosed is:

A = 112812.5 m ^ 2

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3 years ago
Correct answers only!
malfutka [58]

Answer:

$60.5

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3 years ago
The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit
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Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b) We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean \mu, standard deviation \sigma

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b. If the length of pregnancy is in the lowest a​%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

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3 years ago
What other information do you need in order to prove the triangles congruent using the SAS Congruence Postulate?
NNADVOKAT [17]

Answer:

search it on googIe Imao

Step-by-step explanation:

Answer:

Explanation:

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Explanation:

4 0
3 years ago
The town of Madison has a population of 25{,}00025,00025, comma, 000. The population is increasing by a factor of 1.121.121, poi
cestrela7 [59]

Answer:

P(t)=25,000(1.12)^t

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

P(t)=a(b)^t

where

P(t) is the population in Madison

t is the number of years

a is the initial value

b is the factor of growth

we have

a=25,000\ people\\b=1.12

substitute

P(t)=25,000(1.12)^t

3 0
3 years ago
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