Answer:
1. Synthesis
2. Decomposition
3. Single replacement
4. Synthesis
5. Decomposition
6. Synthesis
Explanation:
Kind of a hard picture to look at but let me define each chemical reaction:
Synthesis:
a + b ---> ab In synthesis elements/compounds come together to form new compounds
Decomposition:
ab ---> a + b In decomposition a compound breaks down to form 2 elements/compounds
Single replacement:
a + bc ---> b + ac In a single replacement one element/compound takes the place of another element/compound.
Double replacement
ab + cd ---> ad + bc In a double replacement 2 compounds exchange different elements/compounds.
Now, let's go through the assignment
1. P + O2 --> P4O10 This is a synthesis reaction because the two elements (P and O) came together to form one compound.
2. HgO ---> Hg + O2 This is a decomposition reaction because HgO broke into separate elements Hg and O.
3. Cl2 + NaBr ---> NaCl + Br2 This is a single replacement reaction because chlorine (Cl) replaced the spot of bromine (Br) to bond with sodium (Na).
4. Mg + O2 ---> MgO This is a synthesis reaction because two elements (Mg and O) came together to form one compound.
5. Al2O3 ---> Al + O2 This is a decomposition reactions because Al2O3 broke into separate elements Al and O.
6. H2 + N2 ---> NH3 This is a synthesis reaction because two elements (H and N) came together to form one compound.
<em>I hope this helps!!</em>
<em>- Kay :)</em>
Answer:
114 kPa
Explanation:
Using Gay-Lussac's law you get the equation 
and converting celcius you get the final equation of 
. After dividing 85.5 by 27+273(300) you get 0.285 and then you multiply 0.285 by 127+273 (400). You finally get 114 kPa
Answer:
A strong acid
Any strong acid (such as HCl, HBr, or 
) will completely dissociate forming a very weak conjugate base and H3O which will be acidic.
So the question ask to separate the reaction of the element if your problem into its component half reaction and the best answer or the elements are the following: (Cs-> Cs+ + 1e-) x2 and <span>2e-+Cl2->2Cl-. I hope you are satisfied with my answer and feel free to ask for more </span>
Heat energy is absorbed?...
