I believe the answer is ten pairs...
The two rows each have 3 pairs touching, and the four columns each have 1, which makes 2*3 + 4*1 = 10
Sqrt(486) - sqrt(24) + sqrt(6)
find the factors of 486 that we can remove from under the square root sign
2 * 243
2 * 3 * 81
2 * 3 * 9 * 9 (we have 2 nines, we can move a 9 outside the sqrt sign)
sqrt(486) = 9 sqrt(6)
Repeating for sqrt(24)
2 * 12
2 * 2 * 6
2 * 2 * 2 * 3 (we can move a 2 outside the sqrt
sqrt(24) = 2 sqrt(6)
Finally, add all 3 terms together
9 sqrt(6) - 2 sqrt(6) + sqrt(6)
8 sqrt(6)
8 times square root of 6 is the final answer
-5 and -3 are your numbers.
Answer:
7x−3=7k,x=7k+3,k∈ℤ
Step-by-step explanation:
3x ≡ 2 (mod 7)
3 is a solution, since 3×3−2=7.
All solutions are 3+7ℤ
y=3x−2/7=3(x−3)+7/7=3(x−3)/7+1
7x−3=7k,x=7k+3,k∈ℤ
