Let X be the score on an english test which is normally distributed with mean of 31.5 and standard deviation of 7.3
μ = 31.5 and σ =7.3
Here we have to find score that separates the top 59% from the bottom 41%
So basically we have to find here x value such that area above it is 59% and below it is 49%
This is same as finding z score such that probability below z score is 0.49 and above probability is 0.59
P(Z < z) = 0.49
Using excel function to find the z score for probability 0.49 we get
z = NORM.S.INV(0.49)
z = -0.025
It means for z score -0.025 area below it is 41% and above it is 59%
Now we will convert this z score into x value using given mean and standard deviation
x = (z* standard deviation) + mean
x = (-0.025 * 7.3) + 31.5
x = 31.6825 ~ 31.68
The score that separates the top 59% from the bottom 41% is 31.68
Answer:
x= 200
Step-by-step explanation:
The given equation is:
1/5 x - 2/3 y = 30
The value of y is 15
Put the value of y in the given equation:
1/5 x - 2/3(15) = 30
1/5 x- 10 = 30
Take the L.C.M of the denominator
x-50/5 = 30
Move the denominator to the R.H.S
x-50 = 30*5
x-50 = 150
Combine the like terms
x= 150+50
x = 200
The value of x is 200...
Answer: not 100 percent sure but i think x=37 z=110 y=33
Step-by-step explanation:
Answer:
I feel that the answer is false.
Step-by-step explanation:
Answer:
10
Explanation:
The two shortest sides = the longest side
So I’m this case, the two shortest sides are 7 and 3, which are shown.
Then add:
7 + 3 = 10
