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DanielleElmas [232]
2 years ago
7

Please give me the correct answer

Mathematics
1 answer:
MariettaO [177]2 years ago
8 0

Answer:

Step-by-step explanation:

slant height = l = 15 mm

radius = r = 7 mm

Surface area of cone = πr (l + r) square units

                                  = 3.14 * 7 *(15 + 7)

                                  = 3.14 * 7 * 22

                                 = 483.56 square mm

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HElp me plz and thank you
Inga [223]
I don’t know the answer I’m sorry
4 0
3 years ago
The high school graduating class of 2010 was 260 people. Five years later the high school graduating class was 320 people. By ap
jeka94

Answer:

The high school graduating class changed by approximately 23%

Step-by-step explanation:

we have

The high school graduating class of 2010 was 260 people

Five years later the high school graduating class was 320 people.

we know that

260 people represent the 100%

so

The difference is (320-260)=60 people

using proportion

Find out what percentage represent 60 people

Let

x ----> the percentage that represent 60 people

\frac{260}{100\%}=\frac{60}{x}\\\\x= 100\%(60)/260\\\\x=23.1\%

therefore

The high school graduating class changed by approximately 23%

3 0
3 years ago
I need help please!!
dalvyx [7]

Answer:

y=1/2x +2

Step-by-step explanation:

1/2 is the slope, 2 is the y intercept.

3 0
3 years ago
7 (1) = 7 is an example of what property?
Kitty [74]

Answer:

Identity property

Step-by-step explanation:

Identity property of multiplication: The product of 1 and any number is that number. For example, 7 × 1 = 7 7 \times 1 = 7 7×1=77, times, 1, equals, 7.

I hope it's helpful!

5 0
2 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
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