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Stolb23 [73]
3 years ago
11

imagine that you have a sample of an unknown element and that you know only the elements mass number without directly measuring

the number of protons in the nucleus of the element what other information would you need to know to identify the element?
Physics
1 answer:
Ostrovityanka [42]3 years ago
4 0
If the element's atomic mass is accurate enough you should be able to tell from that , however if it isn't you would most likely want the number of neutrons or electrons contained by the atom.
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Why don't we use more renewable energy sources​
sattari [20]

Answer:

Renewable energy sources 1.Cost more then nonrenewable resources and 2.Are so far not as reliable as nonrenewable energy.

Explanation:

4 0
3 years ago
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Which of the following lists are all renewable resources?
earnstyle [38]

The answer is A.

Hydroelectric, which is usually generating electricity through use of a dam.

Solar, energy from the Sun.

Biomass, organic material formed from plant matter.

3 0
3 years ago
Long, long ago, on a planet far, far away, a physics experiment was carried out. First, a 0.210-kg ball with zero net charge was
tigry1 [53]

Answer:

\Delta V=316167V

Explanation:

The difference of electric potential between two points is given by the formula \Delta V=Ed, where <em>d</em> is the distance between them and<em> E</em> the electric field in that region, assuming it's constant.

The electric field formula is E=\frac{F}{q}, where <em>F </em>is the force experimented by a charge <em>q </em>placed in it.

Putting this together we have \Delta V=\frac{Fd}{q}, so we need to obtain the electric force the charged ball is experimenting.

On the second drop, the ball takes more time to reach the ground, this means that the electric force is opposite to its weight <em>W</em>, giving a net force N=W-F. On the first drop only <em>W</em> acts, while on the second drop is <em>N</em> that acts.

Using the equation for accelerated motion (departing from rest) d=\frac{at^2}{2}, so we can get the accelerations for each drop (1 and 2) and relate them to the forces by writting:

a_1=\frac{2d}{t_1^2}

a_2=\frac{2d}{t_2^2}

These relate with the forces by Newton's 2nd Law:

W=ma_1

N=ma_2

Putting all together:

N=W-F=ma_1-F=ma_2

Which means:

F=ma_1-ma_2=m(a_1-a_2)=m(\frac{2d}{t_1^2}-\frac{2d}{t_2^2})=2md(\frac{1}{t_1^2}-\frac{1}{t_2^2})

And finally we substitute:

\Delta V=\frac{Fd}{q}=\frac{2md^2}{q}(\frac{1}{t_1^2}-\frac{1}{t_2^2})

Which for our values means:

\Delta V=\frac{2(0.21Kg)(1m)^2}{7.7\times10^{-6}C}(\frac{1}{(0.35s)^2}-\frac{1}{(0.65s)^2})=316167V

7 0
3 years ago
After France fell to the Axis powers in 1940, what percentage of the country was placed under German control?
gogolik [260]

Correct answer choice is:

B. 50 percent

Explanation:

France Capitulates to Nazi Germany. On June 22, 1940, the French state approved a cease-fire with Nazi Germany just six weeks after the Nazis began their incursion of Western Europe.

Paris began preparing for combat in September 1939, when Nazi Germany overran Poland, but the combat appeared far beyond until May 10, 1940, when the Germans invaded France and immediately took the French troops. The French administration left Paris on June 10, and the Germans controlled the capital on June 14.

4 0
3 years ago
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In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are 3.00 in. in diameter and have a m
Shalnov [3]

Answer: thickness h = 0.014cm

Question: In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are 3.30 inches in diameter and have a mass of 1.50 g of silicon. How thick (mm) is each wafer if silicon has a density of 2.33 g/cm 3 ? (The volume of a cylinder is V=πr 2 h )

Explanation:

The volume of a cylinder is

Volume V = πr^2h ....1

The density of a material is

Density D = mass m / volume V

D = m/V ....2

Since m and D are given, we can make V the subject of formula.

V = m/D ....3

From equation 1, we need to derive the thickness h of the cylindrical silicon.

h = V/πr^2 .....4

Substituting equation 3 into 4

h = (m/D)/πr^2 .....5

Given.

mass m = 1.50g

density D = 2.33g/cm^3

radius r = diameter/2 = 3.00in/2 = 7.62/2 cm = 3.81cm

Substituting the given values into the equation

h = (1.5/2.33)/(π ×3.81^2)

thickness h = 0.014cm

3 0
3 years ago
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