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babymother [125]
3 years ago
7

Which of these statements suggests that the orbital period of Venus is shorter than that of Saturn?

Physics
1 answer:
Snowcat [4.5K]3 years ago
5 0

Answer:

C) Venus is closer to the Sun than Saturn is.

Explanation:

This is the right answer.

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A car has negative acceleration. What information can you infer from this?
-BARSIC- [3]
The car is not moving,or either it is going backwords
7 0
3 years ago
Read 2 more answers
In Millikan's oil drop experiment an oil drop is at rest between two large plates separated by 1.3 cm when the potential differe
sweet-ann [11.9K]

Answer:

Mass of the oil drop, m=3.01\times 10^{-15}\ kg

Explanation:

Potential difference between the plates, V = 400 V

Separation between plates, d = 1.3 cm = 0.013 m

If the charge carried by the oil drop is that of six electrons, we need to find the mass of the oil drop. It can be calculated by equation electric force and the gravitational force as :

qE=mg

m=\dfrac{qE}{g}

q=6e, e is the charge on electron

E is the electric field, E=\dfrac{V}{d}=\dfrac{400}{0.013}=30769.23\ V/m

m=\dfrac{6\times 1.6\times 10^{-19}\times 30769.23}{9.8}

m=3.01\times 10^{-15}\ kg

So, the mass of the oil drop is 3.01\times 10^{-15}\ kg. Hence, this is the required solution.

5 0
3 years ago
I have these questions I need to find the acceleration, Please explain how to do them, Don't have to explain all xD
34kurt
1. a=(v-v0)/t
a=14 m/s / 2s
a=7 m/s^2
2. <span>a=(v-v0)/t
</span>a=(30 m/s - 0 m/s) / 12 s
a=2.5 m/s^2
3. <span>a=(v-v0)/t
a=(37 m/s - 22 m/s) / 2 s
a= 7.5 m/s^2
4. </span><span>a=(v-v0)/t
a=(12 km/s - 0 km/s)/8 s
a=1.5 km/s^2
etc</span>
7 0
4 years ago
Complete the table
Degger [83]

Answer: the second one

Explanation:

4 0
3 years ago
How high does a rocket have to go above Earth's surface before its weight is half of what it is on Earth?
Contact [7]

Answer:

h=1.6\times 10^6\ m

Explanation:

As we know that the acceleration due to gravity decreases with height.

At certain height it will get to the half of its value on the surface of the earth.

As we know that the weight on the surface of the earth is given as:

w=m.g

where:

m = mass of the object

g = acceleration due to gravity of the substance

Since mass of the substance is constant so the variation is weight is possible only due to change in the acceleration due to gravity.

<u>We know that the variation of the acceleration due gravity with height is given as:</u>

g_{_h}=g\times (1-\frac{2h}{R} )

where:

g_{_h}= value to acceleration due to gravity at height h

g = acceleration due to gravity at the earth's surface

h = height of the object

R = radius of the earth = 6400\ km

according to question the weight becomes half, so,:

4.9=9.8\times (1-\frac{2h}{6400\times10^3} )

h=1.6\times 10^6\ m is the height a rocket has to go above Earth's surface before its weight is half of what it is on Earth.

4 0
3 years ago
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