The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer: 87.5
Step-by-step explanation: 1cm x 25cm = 87.5
Answer: 0.7 is the rate change between the two points
Answer:
A
Step-by-step explanation:
Answer:
48 hats and 104 shirts
Step-by-step explanation:
These are the equations you build from the problem:
h + s = 152
8.50h + 12s = 1656
This is how I solved them:
s= 152-h
8.5h + 12(152-h) = 1656
8.5h + 1824 - 12h = 1656
Solve for h
h= 48
Put this into first equation (h +s = 152) to get s
