Answer:
3 tents hold 2 campers
Step-by-step explanation:
The given relations can be expressed as a single equation in the number of 2-camper tents.
__
Let x represent the number of 2-camper tents. Then the number of 4-camper tents is 6-x, and the total number of campers in tents is ...
2x +4(6 -x) = 18
-2x +24 = 18
-2x = -6 . . . . . . subtract 24
x = 3 . . . . . . . divide by -2
Exactly 3 tents hold 2 campers.
_____
<em>Additional comment</em>
The other 3 tents hold 4 campers.
Another way to consider this is to assume that all tents hold 2 campers, and then realize there are 18 -6×2 = 6 campers left over. If these are placed 2 per tent, then there will be 6/2 = 3 tents with 4 campers. The remaining 3 tents will have 2 campers.
Change the underlined words if it is not correct and write true if it is correct.
<h3>Integers</h3>
<u>1.</u><u> </u><u>P</u><u>ositive</u> integers are not whole numbers.
Negative integers are not whole numbers.
2. All whole numbers are <u>integers</u>.
True
3. <u>Zero</u> is the smallest whole number.
True
4. Any whole number greater than <u>zero</u> is a positive integers.
True
5. Fractions and Decimals are not integer.
6. 1 is a counting number and a positive integers.
True
7. Rational number include all integers , fraction, or terminating decimals.
True
8. Any whole number that is <u>greater</u> than 0 is a negative integers.
- Any whole number that is <u>less</u> than 0 is a negative integers.
Learn more about integers:
brainly.com/question/10853762
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
The answer would be X=5 because 40 - 22 is 18
