$\bf \begin{cases} f(x)=&g(x+1)\\ f(3)=&g(3+1)\\ &g(4)\\[-0.5em] \hrulefill& \hrulefill\\ g(x)=&x^2\\ g(4)=&4^2\\ &16 \end{cases}\qquad \qquad f(3)\implies g(4)\implies 16$

8 0

3 years ago

5 thousand 2 tens 4 ones +4 thousand 3 hundreds 2 ones

Digiron [165]

9 thousands 3 hundreds 2 tens 6 ones
or
9326

3 0

3 years ago

Read 2 more answers

Solve 2^x^2+5x=1/16 without using logarithms. <br> quick plz 15 points

Marianna [84]

Answer:

x=-4, x=-1

Step-by-step explanation:

6 0

3 years ago