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Sati [7]
3 years ago
5

You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a

lmost touches the floor and that its period is 23 s. The acceleration of gravity is 9.81 m/s 2 . How tall is the tower? Answer in units of m
Physics
1 answer:
Elis [28]3 years ago
4 0

Answer:

131.3 m    

Explanation:

Period of pendulum depends on the length of the pendulum. It can be calculated by using the formula:

T=2\pi\sqrt{\frac{l}{g}}

23s=2\pi\sqrt\frac{l}{9.81}\\\Rightarrow 3.66\times 3.13=\sqrt{l}\\\Rightarrow \sqrt l=11.46 \\ \Rightarrow l = 131.3 m

Thus, tower is 131.3 m tall.

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3 years ago
A ray of light has a wavelength of
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Answer:

The wavelength in vacuum is equal to 428.8 nm.

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In 1976, the SR-71A, flying at 20 km altitude (T = –56 0C), set the official jet-powered aircraft speed record of 3530 km/hr (21
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To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.

The altitude is,

z = 20km

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V = 3530km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V = 980.55m/s

From the properties of standard atmosphere at altitude z = 20km temperature is

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Velocity of sound at this altitude is

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Therefore the temperature at its front stagnation point is 689.87K

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