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mash [69]
4 years ago
11

A rock has a mass of 0.27 KG what is the gravitational force on earth due to the rock and what is earths resulting acceleration

earths mass is 6.0×10 to the 24th power kg
Physics
1 answer:
Vitek1552 [10]4 years ago
8 0

1) The gravitational force on Earth is 2.65 N

2) The acceleration of the Earth is 4.4\cdot 10^{-25} m/s^2

Explanation:

1)

First of all, we start by finding the gravitational force exerted by the Earth on the rock. This is equal to the weight of the rock, which is:

F=mg

where:

m = 0.27 kg is the mass of the rock

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F=(0.27)(9.8)=2.65 N

Now we can apply Newton's third law, which states that:

<em>"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".</em>

This means that the force exerted by the Earth on the rock (the weight of the rock) is equal in magnitude to the force exerted by the rock on the Earth: therefore, the gravitational force on Earth is also 2.65 N.

2)

To find the acceleration of the Earth, we use Newton's second law:

F=Ma

where:

F is the net force on the Earth

M is the Earth's mass

a is its acceleration

Here we have:

F=2.65 N

M=6.0\cdot 10^{24} kg is the Earth's mass

And solving for a:

a=\frac{F}{M}=\frac{2.65}{6.0\cdot 10^{24}}=4.4\cdot 10^{-25} m/s^2

Learn more about gravity, forces and Newton laws of motion:

brainly.com/question/3820012

brainly.com/question/11411375

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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In the diagram, q1 = -6.39*10^-9 C and q2 = +3.22*10^-9 C. What is the electric field at point P? pls help
Alexxx [7]

Answer:

Below

Explanation:

First draw the vectors that represent both electric fields.

E1 is the elictric field created by q1, E2 is the one created by q2.

● q1 is negative so E1 will point from P.

● q2 is positive so E2 will point out of P

(Picture below)

■■■■■■■■■■■■■■■■■■■■■■■■■■

The resulting electric field is equal to the sum of the two fields since both vectors are colinear.

Let E be the total field.

● E = E1 + E2

The formula of the electric field intensity is:

● E = K ×(q/d^2)

-K is Coulomb's constant

-d is the distance between the charge and the object ( here P)

-q is the charge

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E1 = K × (q1/d1^2)

The distance between q1 and P is the qum of 0.15 m 0.25 m. (0.4 m)

Coulombs constant is 9×10^9 m^2/C^2

● E1 = 9×10^9 ×[-6.39 × 10^(-9)/ 0.4^2]

● E1 = -359.43 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E2 = K ×(q2/d^2)

The distance between q2 and P is 0.25 m.

● E2 = 9×10^9×[3.22×10^(-9) /0.25^2]

● E2 = 463.68 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E = E1 + E2

● E = -359.43+463.68

● E = 105.25 N/C

4 0
3 years ago
Read 2 more answers
(c) A moving train has a kinetic energy of 8.1 x 10(power of 6)J.
tamaranim1 [39]

the friction force provided by the brakes is 30000 N.

<h3>What is friction force?</h3>

Friction force is the force that opposes the motion between two bodies in contact.

To calculate the average friction force provided by the brakes, we apply the formula below.

Formula:

  • K.E = F'd............. Equation 1

Where:

  • K.E = Kinetic energy of the train
  • F' = Friction force provided by the brakes
  • d = distance

Make F' the subject of the equation

  • F' = K.E/d............ Equation 2

From the question,

Given:

  • K.E = 8.1×10⁶
  • d = 270 m

Substitute these values into equation 2

  • F' = (8.1 ×10⁶)/270
  • F' = 30000 N

Hence, the friction force provided by the brakes is 30000 N

Learn more about friction force here: brainly.com/question/13680415

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Alex17521 [72]

Answer:The net force on the block is zero.

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Block is being pulled upward along an inclined surface at a constant speed

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and change in velocity is equal to acceleration therefore acceleration is zero here i.e. net force is zero acting on the body.

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