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3 years ago

Instrumento que se utiliza para medir fuerzas

Physics

1 answer:

Klio2033 [76]3 years ago

8 0

Answer:

Un medidor de fuerza

A force gauge for all you English speakers

Explanation:

Un medidor de fuerza es un instrumento de medición que se utiliza para medir fuerzas.

A force gauge is a measuring instrument used to measure forces.

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Which of the following expresses the answer to

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Answer: 17.95

Explanation:

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3 years ago

Three sleds (30kg sled connected by tension rope B to 20kg sled connected by tension rope A to 10kg sled) are being pulled horiz

SOVA2 [1]

Answer:

a) a = 2.383 m / s², b) T₂ = 120,617 N , c) T₃ = 72,957 N

Explanation:

This is an exercise of Newton's second law let's fix a horizontal frame of reference

in this case the mass of the sleds is 30, 20 10 kg from the last to the first, in the first the horizontal force is applied.

a) request the acceleration of the system

we can take the sledges together and write Newton's second law

T = (m₁ + m₂ + m₃) a

a = T / (m₁ + m₂ + m₃)

a = 143 / (10 +20 +30)

a = 2.383 m / s²

b) the tension of the cables we think through cable A between the sledges of 1 and 20 kg

on the sled of m₁ = 10 kg

T - T₂ = m₁ a

in this case T₂ is the cable tension

T₂ = T - m₁ a

T₂ = 143 - 10 2,383

T₂ = 120,617 N

c) The cable tension between the masses of 20 and 30 kg

T₂ - T₃ = m₂ a

T₃ = T₂ -m₂ a

T₃ = 120,617 - 20 2,383

T₃ = 72,957 N

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3 years ago

Which are bones of the middle ear that are responsible for vibrating so sound waves can be passed along?

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You need eye drops for your dry eyes. You brought only a few dollars with you to the store. Which is the best method of choosing

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2 years ago

A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for

nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ( $W$ ), measured in newtons, is:

$W = m\cdot g$ (1)

Where:

$m$ - Mass of the block of ice, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 14\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the magnitudes of the weight and normal force of the block of ice are, respectively:

$N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$N = W = 137.298\,N$

And the pull force is:

$F_{pull} = 98\,N$

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

$m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}$ (2)