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Mademuasel [1]
3 years ago
11

Please help thank you

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

a) x=-3

b) y=2,5

have a nice day

Irina18 [472]3 years ago
4 0
Answer:-

x = -3
y= 2.5
P(x,y) = P(-3, 2.5)

Hope it helps!!
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Can u guys answer my question 13 and 14 pls
Alika [10]

Answer:

√2=1.414

then :√8 +2√32 +3√128+4√50

√8=√2³ =2√2

2√32=√2^5 = 4*2√2 = 8√2

3√128 = 3√2^6*2=8*3√2 =24√2

4√50 =4√5²*2= 20√2

add results : 2√2+8√2 +24√2+20√2=54√2

<h2>54√2=54×1.414=76.356 ( it is not in the options)</h2>

x=7-4√3

√x+ 1/√x

√(7-4√3) +1/√(7-4√3) =

(8-4√3)/√(7-4√3)

(8-6.93)/√(7-6.93) = 4 ( after rounded to the nearest whole number)

4 is your answer

3 0
3 years ago
How many times can 10 go into 44
Nitella [24]
4 times because if you count 10, 20, 30, 40, so it has to be 4
5 0
3 years ago
Read 2 more answers
Given f(x) = –7x + 9 and h(x) = –5(–7x + 9), what are the slope and y-intercept of the graph of function h?
taurus [48]

The Slope of f(x) = –7x + 9  is (-7)

The slope of  h(x) = –5(–7x + 9) is (35)

The y-int of h(x) is (-45).

4 0
3 years ago
Read 2 more answers
Which linear inequality is represented by the graph?
Fantom [35]

Answer:

y \leq 1/2x + 2 :)

Step-by-step explanation:

6 0
3 years ago
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In one jar, I have two balls labelled 1 and 2 respectively. In a second jar, I have three balls labelled 0, 1 and 2 respectively
PolarNik [594]

Step-by-step explanation:

this is a kind of trick question, actually.

with whatever we draw, we produce X values as power of 3.

to be precise, we can have only

3⁰ = 1

3¹ = 3

3² = 9

3⁴ = 81

due to the possible combinations of drawn numbers (e.g. 3 cannot be created by a multiplication of 0s, 1s and 2s).

so, mostly, these results cannot be exact factors of 1024.

1024 cannot be divided by 3, nor by 9 nor by 81.

but 1024 is a multiple of 1 (as is every number).

so, we are looking at the probability to get 0 as multiplication result of the numbers on the 2 drawn balls.

the only possibilities are

1 and 0

2 and 0

out of in total 6 (2×3) different outcomes

1 and 0

1 and 1

1 and 2

2 and 0

2 and 1

2 and 2

the probability of this "0" event is again

number of desired outcomes / number of possible outcomes = 2/6 = 1/3

6 0
3 years ago
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