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Mademuasel [1]
3 years ago
11

Please help thank you

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

a) x=-3

b) y=2,5

have a nice day

Irina18 [472]3 years ago
4 0
Answer:-

x = -3
y= 2.5
P(x,y) = P(-3, 2.5)

Hope it helps!!
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Ilia_Sergeevich [38]

Answer:

1 ) alternate interior angle

2) corresponding part of congruent triangle

3) vertically opposite angle

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3 years ago
A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we
kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10  

\mu_{{\overline}{X}} = 3.5

and \sigma_{{\overline}{Y}} = 0.38

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

X_{ij} = The number which comes up  on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

E(X_{ij}) = \frac {1 + 2 + 3 + 4 + 5 + 6}{6}

                            = 3.5       ∀ i = 1(1)10 and j = 1(1)20

and,

E(X^{2}_{ij} = \frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}

                                = \frac {1 + 4 + 9 + 16 + 25 + 36}{6}

                                = \frac {91}{6}

                                \simeq 15.166667

so, Var(X_{ij} = (E(X^{2}_{ij} - {(E(X_{ij})}^{2})

                                    \simeq 15.166667 - 3.5^{2}

                                    = 2.91667

   and \sigma_{X_{ij}} = \sqrt {2.91667}[/tex                                            [tex]\simeq 1.7078261036

Now we get that,

 Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}

We get that Y_{j}'s are iid RV's ∀ j = 1(1)20

Let, {\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}

      So, we get that E({\overline}{Y}) = E(Y_{j})

                                                                 = E(X_{ij}  for any i = 1(1)10

                                                                 = 3.5

and,

       \sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}}                                             = \frac {\sigma_{X_{ij}}}{\sqrt {20}}                                             = \frac {1.7078261036}{\sqrt {20}}                                            [tex]\simeq 0.38

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10  

\mu_{{\overline}{X}} = 3.5

and \sigma_{{\overline}{Y}} = 0.38

                                   

6 0
2 years ago
Solve for x. –2(6 – x) = 3x A. –3 B. 12 C. 3 D. –12
Katen [24]

-2(6-x)= 3x, the solution is  find the value of x,  you must apply distributive property, tho the first term,  -12+2x= 3x⇒ 3x-2x= -12⇒ x = -12, the  answer correct is option D

6 0
2 years ago
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the distance from talamunda to velcratianis 700 miles. the rain takes 5 hours to travel the distance. at what unit rate is the t
belka [17]

140 miles per hour to reach your 700 mile goal.

<h2><u><em>Do NOT try this you will crast and die none of us want that to happen to you!</em></u></h2>
5 0
3 years ago
Blanca's house is assessed at $149,000 and her property tax rate is 2.3%. How much is her annual property taxes?
mrs_skeptik [129]
$3,427 because you take 149000 and multiply by .023 for 2.3%.
5 0
3 years ago
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