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SCORPION-xisa [38]
2 years ago
5

What is the net force URGENT

Physics
2 answers:
Charra [1.4K]2 years ago
7 0
A net force is the sum of all forces acting upon an object. A net force is capable of accelerating mass.
example: if the wheels on a bike push it forward with 5 Newtons & drag is 3 Newtons then the net force is 2 Newtons, forward. 

noname [10]2 years ago
5 0

(10 N to the right) + (15 N to the left)  =  5 N to the left.
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Find the final velocity of a car that accelerates at +2 m/s2 for +4m from an
Stolb23 [73]

Answer:

Explanation:

according to third equation of motion

2as=vf²-vi²

vf²=2as+vi²

vf=√2as+vi²

vf=√2as+vi

vf=√2*2*4+3

vf=√16+3

vf=4+3=7

so final velocity is 7 m/s

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3 years ago
Which muscle is the main muscle of mastication?
Valentin [98]

Answer: Masseter muscle

Explanation:

The masseter muscle is the most powerful muscle of mastication. It is quadrangular in shape and has two parts: deep and superficial. The entirety of the muscle lies superficially to the pterygoids and temporalis, covering them.

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3 years ago
In severe head-on automobile accidents, a deceleration of 60 g’s or more (1 g 5 32.2 ft/s2) often results in a fatality. What fo
Musya8 [376]

Answer:

The resulting force on the child is 3000 lbf

Explanation:

To find the force that acts on a child of 50 lb with a deceleration of 60 g's, we can use the formula:

Force = mass * acceleration

To find the force in lbf, we need to use the mass in lb and the acceleration in g (standard unit of gravity).

So we have that:

Force = 50 * 60

Force = 3000 lbf

So the resulting force on the child is 3000 lbf.

3 0
2 years ago
When, how and where are questions asked during critical inquiry?*<br> 1 p<br> True<br> False
Ierofanga [76]

Answer:

true

Explanation:

7 0
2 years ago
Years ago, a block of ice with a mass of about 20.0 kg was used daily in a home icebox. The temperature of the ice was 0.0°C whe
m_a_m_a [10]

Answer: The ice absorb 6671.1 kJ of thermal energy.

Explanation:

The conversions involved in this process are :

0.00^0C=273K

:H_2O(s)(273K)\rightarrow H_2O(l)(273K)

Now we have to calculate the enthalpy change.

\Delta H=n\times \Delta H_{fusion}

where,

\Delta H = enthalpy change = ?

m = mass of ice = 20.0 kg  = 20.0\times 10^3g    (1kg=1000g)

n = number of moles of ice= \frac{\text{Mass of ice}}{\text{Molar mass of water}}=\frac{20.0\times 10^3g}{18g/mole}=1.11\times 10^3mole

\Delta H_{fusion} = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

Now put all the given values in the above expression, we get

\Delta H=1.11\times 10^3mole\times 6010J/mole

\Delta H=6671100J=6671.1kJ     (1 kJ = 1000 J)

Therefore, the enthalpy change is,  6671.1 kJ

6 0
2 years ago
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