What is the radius of a circle thats the diameter of 480?

Calculate the potential energy stored in an object of mass 50 kg at a height of 20 m from the ground.

bearhunter [10]

Answer:

potential energy=mgh

=50×10×20

=10000 J

8 0

2 years ago

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A food processor draws 8.47 A of current when connected to a potential difference of 110 V.

Andreyy89

Answer:

27.95[kW*min]

Explanation:

We must remember that the power can be determined by the product of the current by the voltage.

$P=V*I$

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

$P=110*8.47\\P=931.7[W]$

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

$Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min]$

3 0

3 years ago

A grape is thrown straight up in the air. If it was thrown at 2 m/s, how high will it go in the air?

ser-zykov [4K]

Answer:

Answer: Height is 0.204 m

Explanation:

At the highest point, it is called the maximum height.

• From third newton's equation of motion:

${ \rm{ {v}^{2} = {u}^{2} + 2gs}}$

• At maximum height, v is zero

• u is initial speed

• g is -9.8 m/s²

• s is the height

${ \rm{0 {}^{2} = {2}^{2} - (2 \times 9.8 \times s)}} \\ \\ { \rm{4 = 19.6s}} \\ \\ { \rm{s = 0.204 \: m}}$

4 0

2 years ago

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How long does it take to drive from one end of california to the other?

evablogger [386]

California is the third largest state and the only two bigger states than California are Alaska and Texas so it really depends on how you want to cross it. There are two routes to cross California depending on how you plan your visit and places you need to see. Depending on the route you take crossing California can take from twelve to almost sixteen hours of drive.

8 0

3 years ago

A constant force of 45 N directed at angle θ to the horizontal pulls a crate of weight 100 N from one end of a room to another a

Rasek [7]

Answer:

$W=173.48J$

Explanation:

information we know:

Total force: $F=45N$

Weight: $w=100N$

distance: $4m$

vertical component of the force: $F_{y}=12N$

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In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

horizontal component: $F_{x}=Fcos\theta$