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Scrat [10]
4 years ago
15

A person standing at the top of mountain aconcagua would be approximately 4.3 mi high. the radius of earth is 3959 mi. what is t

he distance to the horizon from this point? enter your answer as a decimal in the box. round only your final answer to the nearest tenth. mi
Physics
2 answers:
Brums [2.3K]4 years ago
5 0
The answer is 184.6 hope this helped (:
anzhelika [568]4 years ago
5 0

The height of the person and mountain, the radius of the earth, and the distance to the horizon formulate a relationship of Pythagorean theorem.  

Thus , hypotenuse = sum of the radius of the earth and the height of the person and mountain.

C = 3959 mi + 4.3 mi

   = 3963.3 mi

C2 = A2 + B2

B=√C2−A2

B =√(3963.3 mi)2−(3959)2

B =184.6 mi

The distance to the horizon is 184.6 mi

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Answer:

5.2 m

Explanation:

from the question we are given the following

depth of pool (d) = 3.2 m

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point of entry of laser beam from edge of water (l) = 2.5 m

we first have to calculate the angle at which the laser beam enters the water (∝),

tan ∝ = \frac{1}{2.2}

∝ = 24.44 degrees

from the attached diagram, the angle with the normal (i) = 90 - 24.4 = 65.56 degrees

lets assume it is a red laser which has a refractive index of 1.331 in water, and with this we can find the angle of refraction (r) using the formula below

refractive index = \frac{sin i}{sin r}

1.331 = \frac{sin 65.56}{sin r}

r = 43.16 degrees

we can get the distance (x) from tan r = \frac{x}{3.2}

tan 43.16 = \frac{x}{3.2}

x = 3 m

To get the total distance we need to add the value of x to 2.2 m

total distance = 3 + 2.2 = 5.2 m

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