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Scrat [10]
4 years ago
15

A person standing at the top of mountain aconcagua would be approximately 4.3 mi high. the radius of earth is 3959 mi. what is t

he distance to the horizon from this point? enter your answer as a decimal in the box. round only your final answer to the nearest tenth. mi
Physics
2 answers:
Brums [2.3K]4 years ago
5 0
The answer is 184.6 hope this helped (:
anzhelika [568]4 years ago
5 0

The height of the person and mountain, the radius of the earth, and the distance to the horizon formulate a relationship of Pythagorean theorem.  

Thus , hypotenuse = sum of the radius of the earth and the height of the person and mountain.

C = 3959 mi + 4.3 mi

   = 3963.3 mi

C2 = A2 + B2

B=√C2−A2

B =√(3963.3 mi)2−(3959)2

B =184.6 mi

The distance to the horizon is 184.6 mi

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Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un
Naya [18.7K]

Answer:

Specific heat of liquid 1.258 \ J/g^0C.

Explanation:

We know in thermal equilibrium :

Loss in heat by iron block = Gain in heat by liquid .

Specific heat of iron = 0.45 J/g^0C.  { source internet }

Now , loss in heat by iron block = mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.

Heat gain by liquid=mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.

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C_{liquid}=1.258 \ J/g^0C.

7 0
3 years ago
A moon orbits a planet every 42 hours with a mean orbital radius of .002819 AU. The mass of the moon is 8.932 x 1022 kg. Using N
Pepsi [2]

Answer:

The mass of the planet  is 1.9407\times10^{27}\ kg

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon m=8.932\times10^{22}\ kg

We need to calculate the mass of the planet

Using Kepler’s third law

T^2\propto a^3

T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

(151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3

(8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}

(8.932\times10^{22}+m)=1.94087\times10^{27}

m=1.94087\times10^{27}-8.932\times10^{22}

m=1.9407\times10^{27}\ kg

Hence, The mass of the planet  is 1.9407\times10^{27}\ kg

8 0
4 years ago
Question 2 (5 points)
d1i1m1o1n [39]

Answer:

Frequency of sound wave = 198.83 hertz (Approx.)

Explanation:

Given:

Velocity of sound wave in air = 340 m/s

Wavelength = 1.71 meter

Find:

Frequency of sound wave

Computation:

Frequency = Velocity / Wavelength

Frequency of sound wave = Velocity of sound wave in air / Wavelength

Frequency of sound wave = 340 / 1.71

Frequency of sound wave = 198.8304

Frequency of sound wave = 198.83 hertz (Approx.)

6 0
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Rus_ich [418]

Answer:

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8 0
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The horizontal component of the force is 34.5 cos(45) = 24.4 newtons

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