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3 years ago

What measures the amount of displacement in a transverse wave

1 answer:

4 0

Unlike a longitudinal wave, a transverse wave moves about, perpendicular to the direction of propagation. The particles in a transverse wave do not travel along the direction of propagation, but only oscillate up and down on its equilibrium position. With this, the displacement can be determined by measuring (in the case of electronic waves, using an oscilloscope or spectrum analyzer) and setting the desired units to measure the wave in.

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Calculate the speed for each segment on the graph include the units (m/s). Show your calculations, (such as 4/2= 2 m/s)

fgiga [73]

Answer:

v_A = 6 m/s , v_B = 0 m/s , v_C = - 4 m/s , v_D = -4 m/s , v_E = 2.66 m / s

Explanation:

For this exercise we use the definition of average velocity in each segment

v_average = (x₂-x₁) / Δt

segment A of the graph you take the value of distance and time

x₁ = 0 m t₁ = 0 s

x₂ = 60 m t₂ = 10 s

using the average velocity equation and calculate

v_A = (60-0) / (10-0)

v_A = 6 m / s

Segment B

x₁ = 60m

x₂ = 60 m

since the displacement variation is zero (particle stopped) the velocity is zero

v_B = 0 m / s

Segment C and D

x₁ = 60 m t1 = 15 s

x₂ = -40 m t2 = 40 s

v_C = (-40 -60) / (40 -15)

v_C = - 4 m / s

Segment D

how is the same line

v_D = -4 m / s

Segment E

x₁ = -40 m t₁ = 40 s

x₂ = 0 m t₂ = 55 s

v_E = (0- (-40)) / (55 -40)

v_E = 2.66 m / s

6 0

3 years ago

A.) A bullet accelerates at 8000 m/s2

lukranit [14]

Answer:

0.02 s

160 m/s

Explanation:

Given:

Δx = 1.6 m

v₀ = 0 m/s

a = 8000 m/s²

A) Find t.

Δx = v₀ t + ½ at²

1.6 m = (0 m/s) t + ½ (8000 m/s²) t²

t = 0.02 s

B) Find v.

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (8000 m/s²) (1.6 m)

v = 160 m/s

6 0

3 years ago

What tripositive ion has the electron configuration [kr] 4d3 ? what neutral atom has the electron configuration [kr] 5s 2 4d2 ?

tigry1 [53]

(a)

Electronic configuration is given as follows:

$[Kr]4d^{3}$

Since, this is the electronic configuration of ion with+3 that means 3 electrons are removed. On adding the 3 electrons, the electronic configuration of neutral atom can be obtained.

Thus, electronic configuration of neutral atom is $[Kr]4d^{5}5s^{1}$ .

The atomic number of Kr is 36, thus, total number of electrons become 36+6=42.

This corresponds to element: molybdenum. Thus, the tripositive atom will be $Mo^{3+}$ .

(b) The given electronic configuration is $[Kr]5s^{2}4d^{2}$ .

The atomic number of Kr is 36, thus, total number of electrons become 36+4=40.

This corresponds to element zirconium, represented by symbol Zr.

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3 years ago

You are listening to music in your room and you are asked to turn down the volume of your music. When you turn down the volume w

djyliett [7]

The sound waves will get smaller and smaller till there is no more bc it is off.

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4 years ago

the main difference between batholiths and stocks is that stocks are formed deeper in Earth’s surface

11Alexandr11 [23.1K]

<span>A batholith is an exposed area of rock that covers an area larger than 100 square kilometers. Areas smaller than 100 square kilometers are called stocks.</span>

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3 years ago