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soldier1979 [14.2K]
3 years ago
8

3 4 5 5 (1,-1)? -17 2t -37 -44 (x + 4.7 - 5 -5 What does y-5 represent

Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0

Answer:

Please,I don't get your question & kindly be specific

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BRAINLIESTTT ASAP! PLEASE HELP ME :)
ELEN [110]

Answer:

B. False; to be concave the angles cannot be congruent.

Step-by-step explanation:

Regular Polygons are never concave.

5 0
3 years ago
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The width of a rectangle is 7 meters greater than its length. If the area of the rectangle is 170 square meters, write the quadr
Luden [163]
It would be (x)(x+7)=170
If you want it solved, then you would get:
x^{2} +7x-170=0
(x+17)(x-10)=0
And since you can't have a negative length (-17), x=10
So your side lengths would be 10 and 17 (10+7), which would give you an area of 170.
Hope that helps.
8 0
3 years ago
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QUICK I NEED HELP!!
natta225 [31]
7 (6) + 14!!! And this needs to be 20 characters long so I’m adding this
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3 years ago
A box with a square base and open top must have a volume of 296352 c m 3 . We wish to find the dimensions of the box that minimi
mestny [16]

Answer:

  • Base Length of 84cm
  • Height of 42 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, V=x^2h=296352

h=\dfrac{296352}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84

Step 4: Verify that x=84 is a minimum value

We use the second derivative test

A''(x)=\dfrac{2x^3+2370816}{x^3}\\$When x=84$\\A''(x)=6

Since the second derivative is positive at x=84, then it is a minimum point.

Recall:

h=\dfrac{296352}{x^2}=\dfrac{296352}{84^2}=42

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 84cm
  • Height of 42 cm.
5 0
3 years ago
-23-10x ≤ 47 (Solving two step inequalities)
Citrus2011 [14]
Answer: x >= -7

(x is greater than or equal to negative seven)
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2 years ago
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