Answer : 13.64 mL
Explanation : The reaction requires 13.64 mL of NaOH
From the reaction we know that oxalic acid requires two moles of NaOH so we have to calculate the number of moles of both.
0.150 L X 0.1500 moles/L = 2.25 X
So the moles of NaOH will be 2 X (2.25 X ) = 4.5 X
Now, we know the concentration of NaOH as 0.330 M
4.5 X moles / 0.330 moles/L = 0.01364 L or 13.64 mL
So, the volume of NaOH needed to neutralize oxalic acid will be 13.64 mL
H+O>h2o I believe this is the answer
Answer:
B
Explanation:
The properties of a substance can be measured when matter undergoes a change.
Explanation:
A because A galvanic cell consists of two half-cells, such that the electrode of one half-cell is composed of metal A, and the electrode of the other half-cell is composed of metal B; the redox reactions for the two separate half-cells are thus: An+ + ne− ⇌ A.
Explanation:
The molecules move more slowly and their average kinetic energy decreases