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Kitty [74]
3 years ago
9

I need help fast!! Djdndndndndndnnds

Chemistry
1 answer:
adell [148]3 years ago
6 0

Answer:

1st one: carbon dioxide

2nd: Glucose

3rd: Oxygen

4th: Energy

Sorry if this is wrong because I don't see the options!

Hope this helps!

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Q=-76.7kJ

Explanation:

Hello,

In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:

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