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Brut [27]
3 years ago
9

Chemistry! help! please!

Chemistry
2 answers:
VARVARA [1.3K]3 years ago
7 0
It would be 187 75 Re since 76 - 1 is 75 and number 2 would be beta particle and a positron.
Anon25 [30]3 years ago
6 0

1. <em>Nuclear equations </em>

Answer:

D. _{75}^{187}\text{Re}

Explanation:

Your unbalanced nuclear equation is

? \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta }

It is convenient to replace the question mark by an atomic symbol, _{x}^{y}\text{Z}, where x = the atomic number, y = the mass number, and Z = the symbol of the element .

Then your equation becomes

_{x}^{y}\text{Z} \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

x = 76 - 1 = 75

y = 187 + 0 = 187

Element 75 is rhenium (Re), so the nuclear equation becomes

_{75}^{187}\text{Re} \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta

===============

2. <em>Nuclear Particles </em>

Answer:

a. a beta particle and a positron

Explanation:

A beta particle is a negative electron (_{-1}^{0}\text{e}) and a positron is a positive electron (_{+1}^{0}\text{e}).

Thus, both have the same mass but opposite charge.

b. is <em>wrong</em>. A neutron and a proton have the same mass number but slightly different masses. Furthermore, a neutron has no charge, while a proton has a positive charge.

c. is <em>wrong</em>. A proton and an electron and an electron have opposite charges, but a proton has 1836 times the mass of an electron.

d. is <em>wrong</em>. An alpha particle has four times the mass and twice the charge of a proton .

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3 0
3 years ago
2NOCl(g) ↔ 2NO(g) + Cl2(g) with K = 1.6 x10–5. In an experiment, 1.00 mole of pure NOCl and 1.00 mole of pure Cl2 are placed in
poizon [28]

Answer: 3.8\times 10^{-3}M

Explanation:

Moles of  NOCl = 1 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NOCl = 1 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                  2NOCl(g)\rightleftharpoons 2NO(g)+Cl_2(g)

Initial conc.          1 M                      0M          1 M

At eqm. conc.     (1-2x) M              (2x) M       (1+x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}

The K_c= 1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

{1.6\times 10^{-5}}=\frac{(2x)^2\times (1+x)}{(1-2x)^2}

By solving the term 'x', we get :

x=0.0019

Concentration of NO at equilibrium= (2x) M  =  2\times 0.0019=3.8\times 10^{-3}M

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3 years ago
Can anyone draw a diagram of a liebigs condenser
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I googled it, here it is lol

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3 years ago
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