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Brut [27]
4 years ago
9

Chemistry! help! please!

Chemistry
2 answers:
VARVARA [1.3K]4 years ago
7 0
It would be 187 75 Re since 76 - 1 is 75 and number 2 would be beta particle and a positron.
Anon25 [30]4 years ago
6 0

1. <em>Nuclear equations </em>

Answer:

D. _{75}^{187}\text{Re}

Explanation:

Your unbalanced nuclear equation is

? \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta }

It is convenient to replace the question mark by an atomic symbol, _{x}^{y}\text{Z}, where x = the atomic number, y = the mass number, and Z = the symbol of the element .

Then your equation becomes

_{x}^{y}\text{Z} \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

x = 76 - 1 = 75

y = 187 + 0 = 187

Element 75 is rhenium (Re), so the nuclear equation becomes

_{75}^{187}\text{Re} \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta

===============

2. <em>Nuclear Particles </em>

Answer:

a. a beta particle and a positron

Explanation:

A beta particle is a negative electron (_{-1}^{0}\text{e}) and a positron is a positive electron (_{+1}^{0}\text{e}).

Thus, both have the same mass but opposite charge.

b. is <em>wrong</em>. A neutron and a proton have the same mass number but slightly different masses. Furthermore, a neutron has no charge, while a proton has a positive charge.

c. is <em>wrong</em>. A proton and an electron and an electron have opposite charges, but a proton has 1836 times the mass of an electron.

d. is <em>wrong</em>. An alpha particle has four times the mass and twice the charge of a proton .

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A smaple of 1cm cuvette gives an absorbance reading of 0.558. if they absorptivity for this sample is 15000l/(mol.cm), what is t
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To solve this problem, we use Beer's Law: A= ε.l.c
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The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

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For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

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