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Brut [27]
3 years ago
9

Chemistry! help! please!

Chemistry
2 answers:
VARVARA [1.3K]3 years ago
7 0
It would be 187 75 Re since 76 - 1 is 75 and number 2 would be beta particle and a positron.
Anon25 [30]3 years ago
6 0

1. <em>Nuclear equations </em>

Answer:

D. _{75}^{187}\text{Re}

Explanation:

Your unbalanced nuclear equation is

? \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta }

It is convenient to replace the question mark by an atomic symbol, _{x}^{y}\text{Z}, where x = the atomic number, y = the mass number, and Z = the symbol of the element .

Then your equation becomes

_{x}^{y}\text{Z} \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

x = 76 - 1 = 75

y = 187 + 0 = 187

Element 75 is rhenium (Re), so the nuclear equation becomes

_{75}^{187}\text{Re} \longrightarrow _{76}^{187}\text{Os} + _{-1}^{0}\beta

===============

2. <em>Nuclear Particles </em>

Answer:

a. a beta particle and a positron

Explanation:

A beta particle is a negative electron (_{-1}^{0}\text{e}) and a positron is a positive electron (_{+1}^{0}\text{e}).

Thus, both have the same mass but opposite charge.

b. is <em>wrong</em>. A neutron and a proton have the same mass number but slightly different masses. Furthermore, a neutron has no charge, while a proton has a positive charge.

c. is <em>wrong</em>. A proton and an electron and an electron have opposite charges, but a proton has 1836 times the mass of an electron.

d. is <em>wrong</em>. An alpha particle has four times the mass and twice the charge of a proton .

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How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
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First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

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2) Vaporization

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3) Vapor heating

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Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

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<h2>Frequency</h2>

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

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