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chubhunter [2.5K]

3 years ago

14

A certain rectangular lacrosse field measures 120 yards long by 66 yards wide. What is the area of the lacrosse field in square

yards

1 answer:

Ne4ueva [31]3 years ago

5 0

The answer is 7920 square yards.

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if two points are givin, then exactly one line can be drawn through those two points. which geomerty trem does the statement rep

Natalka [10]

Answer:

the correct answer is

Step-by-step explanation:

hope this helps u!!

8 0

3 years ago

A car is purchased for a downpayment of $3,000 with an additional monthly payment of $400 for 36 months. The

bonufazy [111]

Answer:

$3400 after one year

$17400 after the 36 months

Step-by-step explanation:

3000+400*1=3400

3000+400*36=17400

6 0

3 years ago

Simplify the expression: 8–3w+3w+2–8

Ray Of Light [21]

Combine like terms. 3w-3w=0. 8+2-8=2. So the answer is 2. I hope this helps!

4 0

3 years ago

What is the answer Timothy curtain company is making curtains for a local hotel he wants each certain to be 48 inches long at th

Travka [436]

Answer:

180 feet

Step-by-step explanation:

The length of each curtain = 48 inches. Let the length of the curtain in feet be represented by x.

But,

1 inch = 12 feet

So that,

48 inches = x feet

⇒ x = $\frac{48}{12}$

= 4

Thus,

48 inches = 4 feet

The number of feet of fabric needed for 45 curtains can be determined as:

45 x 4 feet = 180 feet

Therefore, 180 feet of fabric would be needed to make 45 curtains.

7 0

3 years ago

6. Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined, enter UND

Darya [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

6a

$V(3) = 113.112$

6b

$V(\frac{3}{2}) = 14.139$

6c

$V(2r) = 33.514r^3$

7a

$h(5) = 0$

7b

$h(t) = -5.76$

7c

$h(x+5) = x(x+5)$

Step-by-step explanation:

Considering the question 6

The function given is $V(r) = \frac{4}{3} \pi r^3$

For V(3) we have

$V(3) = \frac{4}{3} \pi 3^3$

$V(3) = \frac{4}{3} * 3.142 * 3^3$

$V(3) = 113.112$

For $V(\frac{3}{2})$

$V(\frac{3}{2}) = \frac{4}{3} * \pi * (\frac{3}{2})^3$

$V(\frac{3}{2}) = \frac{4}{3} * 3.142 * (\frac{3}{2})^3$

$V(\frac{3}{2}) = 14.139$

For V(2r)

$V(2r) = \frac{4}{3} \pi (2r)^3$

$V(2r) = \frac{4}{3} * 3.142*8r^3$

$V(2r) = 33.514r^3$

Considering the question 7

The function given is $h(t) = t^2 - 5t$

For h(5)

$h(5) = 5^2 - 5(5)$

$h(5) = 0$

For h(1.8)

$h(t) = 1.8^2 - 5(1.8)$

$h(t) = -5.76$

For h(x+ 5)

$h(x+5) = (x+5)^2 - 5(x+5)$

$h(x+5) = x^2 + 25+10x-5x-25$

$h(x+5) = x(x+5)$

7 0

3 years ago