1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Montano1993 [528]
3 years ago
11

The resistance created by waves on a 120-m-long ship is tested in a channel using a model that is 4 m long Y Part A If the ship

travels at 70 km/h. what should be the speed of the model?
Physics
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

V_m = 12.78 km/hr

Explanation:

given,

length of the ship = 120 m

length of model of the ship = 4 m

Speed at which the ship travels = 70 km/h

speed of model = ?

by using froude's law

  F_r = \dfrac{V}{\sqrt{L g}}

for dynamic similarities

  (\dfrac{V}{\sqrt{L g}})_P = (\dfrac{V}{\sqrt{L g}})_{model}

  (\dfrac{V_p}{\sqrt{L_p}}) = (\dfrac{V_m}{\sqrt{L_m}})

  (\dfrac{70}{\sqrt{120}}) = (\dfrac{V_m}{\sqrt{4}})

          V_m = 12.78 km/hr

hence, the velocity of model will be 12.78 km/h

You might be interested in
What is the resistivity of a wire of 1.3 mm diameter, 2.3 m length, and 61 ms resistance. Number Units The number of significant
kakasveta [241]

Answer:

\rho = 3.68 *10^{-8} Ω. m

Explanation:

The resistance is given as

R = \frac{\rho L}{A}

Where A IS Cross sectional area of wire= \pi r^{2}

therefore resistivity \rho can be wrtten as

\rho = \frac{\pi Rd^{2}}{4L}

Putting all value to get resistivity value\rho =\frac{\pi* 61*10^{-3}* (1.33*10^{-3})^{2}}{4*2.3}

\rho = 3.68 *10^{-8} Ω. m

3 0
4 years ago
1. An astronaut is getting ready to explore. If his mass is 60 kg, what is his weight<br> on Earth?
kifflom [539]

Answer:

<h3>The mass of an object is the same on Earth, in orbit, or on the surface of the Moon. ... 1N=1kg ⋅m/s2. 1 N = 1 kg · m/s 2 . ... The gravitational force on a mass is its weight. ... </h3>

Explanation:

<h3>ILY:)</h3>

3 0
3 years ago
Read 2 more answers
A 783kg elevator rises straight up 164 meters. What is the potential energy of the elevator?
Vilka [71]

Answer:

potential \: energy = mgh \\ m = 783 \\ g = 10 \\ h = 164 \\ pe = 783 \times 10 \times 164 \\ =  7830 \times 164 \\  = 1284120 \: joule \\ thank \: you

8 0
2 years ago
Read 2 more answers
a motorcycle accelerates from 15 m/s to 20 m/s over a distance of 50 meters. what is its average acceleration?
devlian [24]
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s² So the average acceleration is 1.75 m/s²
5 0
3 years ago
What is potential energy
valkas [14]

Answer:

Potential energy is energy that is stored – or conserved - in an object or substance. This stored energy is based on the position, arrangement or state of the object or substance. You can think of it as energy that has the 'potential' to do work.

6 0
3 years ago
Read 2 more answers
Other questions:
  • Planets use carbon dioxide for?
    11·2 answers
  • Which kingdom<br> does the owl belong to
    11·1 answer
  • A quarterback throws a football with an initial velocity v at an angle θ above horizontal. Assume the ball leaves the quarterbac
    14·1 answer
  • Wood iron glass aluminum and paper which substances have high thermal conductivity
    13·2 answers
  • Which of the following statements is true? A. Balanced forces do not cause a change in motion. B. Balanced forces always cause a
    14·2 answers
  • The mass of a star can be determined by studying
    14·2 answers
  • A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial speed of 32 m/s, what is its new speed?
    9·1 answer
  • Question 3 of 10
    5·1 answer
  • Find preposition of the following lines
    9·1 answer
  • A current carrying wire of length 50cm is positioned perpendicular to a uniform magnetic field
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!