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kifflom [539]
3 years ago
12

A safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. What is the probability of a lock

without all even digits? There to get a lock code with all even digits. There are 3,024 different 4-digit lock codes. There are to get a lock code without all even digits. The probability of a 4-digit lock code without all even digits is
Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

To find the total number of outcomes for this event, find the permutation of ⇒ 9.

The total number of outcomes is 3024

The total number of favorable outcomes is a permutation of ⇒ 4

The probability that the lock code consists of all even digits is ⇒ 24 out of 3,024.

Step-by-step explanation:

Elenna [48]3 years ago
6 0
Probability of lock code with all even digits =  (4/9) ^ 4 =  256/6561 = 0.039 

So probabiilty of lock without all even digits = 1 - 0.039  =  0..961.
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<u>Algebra I</u>

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<u>Calculus</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
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