Question

A safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. What is the probability of a lock without all even digits? There to get a lock code with all even digits. There are 3,024 different 4-digit lock codes. There are to get a lock code without all even digits. The probability of a 4-digit lock code without all even digits is

Answer 1

Answer:

To find the total number of outcomes for this event, find the permutation of ⇒ 9.

The total number of outcomes is 3024

The total number of favorable outcomes is a permutation of ⇒ 4

The probability that the lock code consists of all even digits is ⇒ 24 out of 3,024.

Step-by-step explanation:

Answer 2

Probability of lock code with all even digits =  (4/9) ^ 4 =  256/6561 = 0.039 

So probabiilty of lock without all even digits = 1 - 0.039  =  0..961.