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vlabodo [156]
3 years ago
5

Djrigisbtifbebfj djjsbFiebdiwbdioc9sj

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

dsjklejioslmßfejazkfjkejsklfjkfjljakfj ajkldjfkajkfdjakl

Step-by-step explanation:

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Solve for w.<br><br> 5w + 9z = 2z + 3w<br><br> w = z<br> w = z<br> w = –2z<br> w = –7z
Semenov [28]

5w + 9z = 2z + 3w

Move terms with w to the left - subtract 3w from both sides

2w + 9z = 2z

Subtract 9z from both sides

2w = -7z

Divide both sides by 2

w = \frac{-7}{2}z

6 0
3 years ago
Final question of the 9 and with most of the point i can give so people dont pour in
Mrrafil [7]

Answer:

A=49 degree

a=13.5

b=11.7

Step-by-step explanation:

8 0
3 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
Find the missing side lengths. Leave your answers as radicals in simplest<br> form.
JulsSmile [24]
X=40
Y=20. Are the awnsers
8 0
3 years ago
There so a fraction that is equivalent to 25/30. The difference between the denominator and the numerator is 1. The sum of the d
fenix001 [56]
The fraction is 5/6
(difference is 1 and 5+6=11)
4 0
3 years ago
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