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Julli [10]
3 years ago
14

A piece of wood is floating in a tub of water. a second piece of wood rest on top of the first piece; it does not touch the wate

r. if the second piece is removed from the first and placed in the water, what happens to the water level in the tub
Physics
1 answer:
barxatty [35]3 years ago
5 0
The water leval in the tub will stay the same due to the law of water replacement.

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Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it
lesya692 [45]

Answer:

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

Explanation:

As we know that the mass is revolving with constant angular speed in the circle of radius R

So we will have

\theta = \omega t

now the position vector at a given time is

r = Rcos\theta \hat i + R sin\theta \hat j

now the linear velocity is given as

v = \frac{dr}{dt}

v = (-R sin\theta \hat i + R cos\theta \hat j)\frac{d\theta}{dt}

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

6 0
3 years ago
Help me please
agasfer [191]

Answer:

For a velocity versus time graph how do you know what the velocity is at a certain  time?

Ans: By drawing a line parallel to the y axis (Velocity axis) and perpendicular to the co-ordinate of the Time on the x axis (Time Axis). The point on the slope of the graph where this line intersects, will be the desired velocity at the certain time.

_____________________________________________________

How do you know the acceleration at a certain time?

Ans: We\ know\ that\ acceleration = \frac{Final\ velocity-Initial\ Velocity}{Time\ taken}

Hence,

By dividing the difference of the Final and Initial Velocity by the Time Taken, we could find the acceleration.

_________________________________________________________

How do you know the  Displacement at a certain time?

Ans: As Displacement equals to the area enclosed by the slope of the Velocity-Time Graph, By finding the area under the slope till the perpendicular at the desired time, we find the Displacement.

_________________________________________________________

4 0
3 years ago
A ball is thrown vertically upward and then comes back down. During the ball's flight up and down, its velocity and acceleration
Dovator [93]

During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

  • The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).
  • When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

To know more about velocity and acceleration vectors

brainly.com/question/13492374

#SPJ4

6 0
2 years ago
Give two examples of how magnetic domains and electric charges are similar
zhannawk [14.2K]
The fundamental closeness is they have a similar like charges repulse each other, distinctive charges pull in each other. While their distinction is that attractive "charges" can't be isolated. At any rate, so far it has not been accomplished. I trust this makes a difference.
3 0
3 years ago
On the moon, which objects would fall with the same acceleration?
I am Lyosha [343]
On a planet/celestial body with gravity, the acceleration of gravity is the same for everything.  Therefore, all three options are correct.

Hope this helps!
6 0
4 years ago
Read 2 more answers
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