A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2
Answer:
F=126339.5N
Explanation:
to find the necessary force to escape we must make a free-body diagram on the hatch, taking into account that we will match the forces that go down with those that go up, taking into account the above we propose the following equation,
Fw=W+Fi+F
where
Fw= force or weight produced by the water column above the submarine.
to fint Fw we can use the following ecuation
Fw=h. γ. A
h=distance
γ=
specific weight for seawater = 10074N / m ^ 3
A=Area
Fw=28x10074x0.7=197467N
w is the weight of the hatch = 200N
Fi is the internal force of the submarine produced by the pressure = 1atm = 101325Pa for this we can use the following formula
Fi=PA=101325x0.7=70927.5N
finally the force that is needed to open the hatch is given by the initial equation
Fw=W+Fi+F
F=Fw-W+Fi
F=197467N-200N-70927.5N
F=126339.5N
The answer to the question would be Refraction.
as we know the two possible answers are refraction and reflection. The questions shows a decrease in speed thus being refraction as a ray in a reflection would not lose its speed. Hope this helps!
22N to the right and 13N to the left
Forces are in opposite directions so you subtract the bigger force from the smaller force
Magnitude of force= 22N -13N
= 9N
net force direction is to the right
Answer:
34 m/s
Explanation:
The law of conservation of linear momentum dictates that the sum of initial and final momentum should be equal. Momentum is a product of mass and velocity.
Since the canon recoils, its recoil velocity is opposite hence
MV=nu where M and n are mass of cannon and cannoball respectively, v and u are the velocities of cannon and cannon balls respectively.
Substituting 200 kg for M and 1.7 m/s for v then 10 kg for n
200*1.7=10u
U=200*1.7/10=34 m/s
