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gayaneshka [121]
1 year ago
7

A ball is thrown vertically upward and then comes back down. During the ball's flight up and down, its velocity and acceleration

vectors are?
Physics
1 answer:
Dovator [93]1 year ago
6 0

During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

  • The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).
  • When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

To know more about velocity and acceleration vectors

brainly.com/question/13492374

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Answer:

80m<em>/</em><em>s</em>

Explanation:

Final velocity is given by

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when a motorcyclist starts from rest, initial velocity (u) =0

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that's the answer

8 0
3 years ago
Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between
Romashka [77]

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

\Delta V=Ed

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\Delta V is the potential difference

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In this problem, we have:

\Delta V=750 V is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m

6 0
3 years ago
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________b_____ 7 km east

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|a

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5 0
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