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Alex787 [66]
2 years ago
15

Neil studied how a pulley helps move an object. Neil tied a rope to an object with a mass of 10 kilograms (kg) and attached it t

o a pulley. He then pulled down on the rope. When Neil pulled down on the rope, which did he most likely learn about the force required to lift the object? Group of answer choices
1. It was half of the weight of the object.
2. It was equal to the weight of the object
3. It was two times the weight of the object.
4. It was three times the weight of the object.
Physics
1 answer:
SashulF [63]2 years ago
3 0

Answer:2

Explanation:

Given

mass of object m=10\ kg

weight of object =mg

Weight=10\times 9.8

If body is being pulled with constant velocity then the net force on body is zero i.e.

Force=weight of object

F=98\ kg

force is equal to weight of object

option 2 is correct

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The difference between Lincoln's plan of reconstruction and the Radical Republicans' is that Lincoln wanted to reunite the union
Oduvanchick [21]

Answer:

The differences between the Lincoln, Johnson, and Congress Reconstruction plans include: Although both the Lincoln and Johnson plan were open to readmission of the southern States, Congress claimed that the two administrations were too lenient and sought stiffer punishment for the States

The aspect of Abraham Lincoln's plan for reconstruction in the South that made it differ from the plan of congressional leaders was that Lincoln's plan was more focused on helping the South rebuild than on punishing it and the Radical Republicans' reconstruction offered all kinds of new opportunities to African Americans, including the vote (for males), property ownership, education, legal rights, and even the possibility of holding political office. By the beginning of 1868, about 700,000 African Americans were registered voters.

Reconstruction encompassed three major initiatives:

1. restoration of the Union

2. transformation of southern society

3.enactment of progressive legislation favoring the rights of freed slaves

6 0
2 years ago
Starting from rest, a racing car has a displacement of 201 m, S, in the first 5.0 s of uniform acceleration. What is the car's a
mihalych1998 [28]

Answer:

Explanation:

s = ½at²

a = 2s/t²

a = 2(201) / 5.0²

a = 16.08

a = 16 m/s²

8 0
2 years ago
A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change. A) True B) False
bixtya [17]

Answer:

False

Explanation:

Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.

\epsilon=\dfrac{-d\phi}{dt}

The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.

Hence, it is false.

3 0
3 years ago
find the rate of positive acceleration of an automobile which went from a complete stop to a velocity of 30 meters per second in
maks197457 [2]

Answer:

3 m/s^2

Explanation:

acceleration= Change in velocity/time

= 30-0 / 10

= 30/10

=3 m/s^2

3 0
3 years ago
A woman can row a boat at 5.60 km/h in still water. (a) If she is crossing a river where the current is 2.80 km/h, in what direc
katrin2010 [14]

Answer:

a) θ=210°, b) t=1.155hr, c) t=1.333hr, d) t=1.333hr, e) θ=180° (straight across), f) t=1hr.

Explanation:

So, the very first thing we nee to do when solving this problem is draw a diagram that represents it. In the attached picture I show a diagram for each part of this problem.

part a)

So, for her to move in a direction directly opposite her starting point, the x-component of her velocity must be de same as the velocity of the river in the opposite direction. We can use this fact to find the angle we need. If we analize the triangle I drew in the diagram, we can ses that:

cos \theta = \frac {V_{river}}{V_{boat}}

When solving for theta, we get that:

\theta =cos^{-1} ( \frac {V_{river}}{V_{boat}})

so now we can substitute the corresponding values:

\theta =cos^{-1} ( \frac {2.80km/hr}{5.60km/hr}})

Which yields:

\theta = 60^{o}

but we are measuring the angle relative to the line perpendicular to the river, positive if down the river. So we need to subtract the angle from 270° so we get:

θ=270°-60°=210°

part b)

for part b, we need to find what the y-component for the velocity of the boat is for an angle of 210° as shown in the problem, so we get that:

V_{y}=5.60km/hr*cos(210^{o})

V_{y}=-4.85km/hr

The woman will head in a negative 5.60km distance from one side to the other, so we get that the time it takes her to go to the other side of the river is:

t=\frac{y}{V_{y}}

t=\frac{5.60km}{4.85km/hr}=1.155hr

part c)

In order to find the time it takes her to travel 2.80km down and up the river, we need to find the velocities she will have in both directions. First, down stream:

V_{ds}=V_{river}+V{boat}

V_{ds}=2.80km/hr+5.60km/hr=8.40km/hr

and now up stream:

V_{us}=V_{boat}-V{river}

V_{us}=5.60km/hr-2.80km/hr=2.80km/hr

Once we got these two velocities we will now need to find the time to take each trip:

time down stream:

t_{ds}=\frac{x}{v_{ds}}

t_{ds}=\frac{2.80km}{8.40km/hr}=0.333hr

and the time up stream:

t_{us}=\frac{x}{v_{us}}

t_{us}=\frac{2.80km}{2,80km/hr}=1hr

so the total time will be:

t_{ds}+t_{us}=0.333hr+1hr=1.333hr

d) the time it takes the boat to go upstream and then downstream for the same distance is the same as the time we got on part c, since both times will be the same but they will come in different order, but their sum will be just the same:

t=1.333hr

e) For her to cross the river faster, she must row in a 180° direction (this is in a direction straight accross the river) that way she will use all her velocity to move across the river. (Even though she will move a certain distance horizontally and will not reach a point opposite to the starting point.)

f) In order to find the time it takes her to get to the other side, we need to divide the distance into the velocity of the boat.

t=\frac{d}{v_{boat}}

t=\frac{5.60km}{5.60km/hr}

so

t= 1hr

4 0
3 years ago
Read 2 more answers
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