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Mashcka [7]
3 years ago
5

Suppose that you repeated questions 5 and 6 using two line segments of your choice. The line segments could be any length and in

any orientation as long as the midpoints were marked correctly and coincided with each other. Would you reach the same conclusion that you reached in question 7? How does your conclusion relate to the diagonals of a parallelogram?
Mathematics
2 answers:
zzz [600]3 years ago
7 0

Yes, I would reach the same conclusion. The line segments that I’m drawing represent the diagonals of a parallelogram. If the intersection point of the diagonals divides each diagonal in half, then the quadrilateral that belongs to the diagonals is a parallelogram.

nataly862011 [7]3 years ago
5 0

Answer:

Is there a picture with it?

Step-by-step explanation:

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Answer:

n=13/7

Step-by-step explanation:

2n+4+6*2=-9*2+8(2n+1)

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16+18=16n-2n+8

34=14n+8

34-8=14n

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n=13/7

8 0
3 years ago
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4+3(2r+2s)+3r<br><br> Simplify this expression
Ipatiy [6.2K]
Hello!

First you can distribute the 3

4 + 6r + 6s + 3r

Then you combine like terms

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The answer is 9r + 6s + 4

Hope this helps!
3 0
2 years ago
Two triangles are similar with a scale factor of 3. The preimage triangle has a base of 7 inches and a height of 10 inches. What
vaieri [72.5K]

Answer:

<u>The area of the larger triangle is 315 inches²</u>

Step-by-step explanation:

1. Let's review all the information provided for answering the questions properly:

Pre-image triangle has a base of 7 inches and a height of 10 inches

Scale used : Factor of 3

2. What is the area of the larger triangle??

For calculating the area of the larger triangle, we use the scale this way:

Base = 7 inches * 3

21 inches

Height = 10 inches * 3

30 inches

Area of the larger triangle = 1/2 (Base * Height)

Area of the larger triangle = 1/2 (21 * 30)

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2 years ago
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Step-by-step explanation:

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61.538

Step-by-step explanation:

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