Given:
r = radius = 4
h = height = 12
dr = error in radius = 0.2
What we want to find
dV = error in volume
Use the derivative to find the differential dV
V = pi*r^2*h
dV/dr = d/dr[ pi*r^2*h ]
dV/dr = 2pi*r*h
dV = 2pi*r*h*dr
dV = 2pi*4*12*0.2
dV = 19.2pi
So if the error in measuring the radius is +-0.2 inches, then the error in the cylinder volume is +-19.2pi cubic inches (we either measure the volume to be 19.2pi cubic inches too big, or 19.2pi cubic inches too small)
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Final Answer: Plus or minus 19.2pi cubic inches
Note: your teacher may want you to drop the "plus or minus" part
10 tickets for $1.00 is the better buy because because that would make each ticket 10cents which is cheaper
A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244
