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Arte-miy333 [17]

3 years ago

8

How to keep a 1lb ice cube from melting for 24 hours

1 answer:

iren2701 [21]3 years ago

7 0

Answer: Put it in the freezer

I honestly dont know lol

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How do i get the correct answer for 0.429m to mm

krok68 [10]

the answer for 0.429m to mm is 429

6 0

2 years ago

Read 2 more answers

A transverse wave on a string is described by the following wave function.y = (0.090 m) sin (px/11 + 4pt)(a) Determine the trans

alukav5142 [94]

Explanation:

(a) It is known that equation for transverse wave is given as follows.

y = $(0.09 m)sin(\pi \frac{x}{11} + 4 \pi t)$

Now, we will compare above equation with the standard form of transeverse wave equation,

y = $A sin(kx + \omega t)$

where, A is the amplitude = 0.09 m

k is the wave vector = $\frac{\pi}{11}$

$\omega$ is the angular frequency = $4\pi$

x is displacement = 1.40 m

t is the time = 0.16 s

Now, we will differentiate the equation with respect to t as follows.

The speed of the wave will be:

v(t) = $\frac{dy}{dt}$

v(t) = $A \omega cos(kx + \omega t)$

v(t) = $(0.09 m)(4\pi) cos(\frac{\pi \times 1.4}{11} + 4 \pi \times 0.16)$

v(t) = -0.84 m/s

The acceleration of the particle in the location is

a(t) = $\frac{dv}{dt}$

a(t) = $-A \omega 2sin(kx + \omega t)$

a(t) = $-(0.09 m)(4 \pi)2 sin(\frac{\pi \times 1.4}{11} + 4\pi \times 0.16)$

a(t) = -9.49 $m/s^{2}$

Hence, the value of transverse wave is 0.84 m/s and the value of acceleration is 9.49 $m/s^{2}$ .

(b) Wavelength of the wave is given as follows.

$\lambda = \frac{2\pi}{k}$

$\lambda = (frac{2\pi}{\frac{\pi}{11})
$

$\lambda$ = 22 m

The period of the wave is

T = $\frac{2 \pi}{\omega}$

T = $\frac{2 \pi}{4 \pi}$

= 0.5 sec

Now, we will calculate the speed of propagation of wave as follows.

v = $\frac{\lambda}{T}$

= $\frac{22 m}{0.5 s}$

= 44 m/s

therefore, we can conclude that wavelength is 22 m, period is 0.5 sec, and speed of propagation of wave is 44 m/s.

7 0

3 years ago

An arrow with a mass of 45.3g is fired vertically into the air at 82.5m/s from a height of 1.41m. Calculate the speed of the arr

jolli1 [7]

Answer:

78.156 m/s

Explanation:

(assuming no upthrust from the air on the arrow)

Ball has a motion only under ther gravity

Apply motion equation upwards

(g = 10m/s²)

V² = U² + 2as

= 82.5² + 2*(-10)*(36.3-1.41.)

= 6108.45

V = 78.156 m/s

8 0

3 years ago

An alloy of two metals has a volume V and a mass m. Density of metals p1 and p2. What is the mass of the first metal in the allo

timurjin [86]

Answer:

the right answer is density of metal v1.v2

3 0

2 years ago

SPEAR is a storage ring at the Stanford Linear Accelerator which has a circulating beam of electrons that are moving at nearly t

DaniilM [7]

Answer:

$2.4\times 10^{12}$

Explanation:

We are given that

Speed of light,v= $2.998\times 10^8 m/s$

Diameter of ring,d=92 m

Radius,r= $\frac{d}{2}=\frac{92}{2}=46 m$

Current, I=0.40 A

We have to find the number of electrons in the beam.

We know that

Current,I= $\frac{q}{t}$

Where q= ne

$e=1.6\times 10^{-19} C$

Using the formula

$0.40=\frac{1.6\times 10^{-19}n}{\frac{2\pi r}{v}}$

$0.40=\frac{1.6\times 10^{-19}n\times v}{2\pi r}$

$0.40=\frac{1.6\times 10^{-19}n\times 2.998\times 10^8}{2\pi\times 46}$

$n=\frac{0.40\times 2\pi\times 46}{1.6\times 10^{-19}\times 2.998\times 10^8}=2.4\times 10^{12}$

7 0

3 years ago