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Mariana [72]
3 years ago
7

A student states that exercise will affect the number of times a person can squeeze a clothespin in a certain amount of time. An

experiment is carried out to test this hypothesis. A group of 10 students sits quietly before squeezing a clothespin as many times as possible during a time period of 1 minute. A second group of 10 students does 25 jumping jacks before squeezing a clothespin as many times as possible during a time period of 1 minute.
What is the dependent variable in the experiment described above?


Question 1 options:


A.Type of exercise



B.Number of times a person can squeeze a clothespin



C.Number of students in each group



D.Amount of time spent exercising
Chemistry
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

B.Number of times a person can squeeze a clothespin

Explanation:

Hello,

Since the idea is to detect the effect of the previous exercise on the number of times a person can squeeze a clothespin and this is done by setting a specific time of 1 minute (a controlled variable) and subsequently record the times, one can state that the times the clothespin is squeezed depend both on the type of exercise and the time, thus those times turn out into the dependent variable.

Best regards.

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im sorry but um can someone go see if they can help me with my most recent question...if you don't know the answer its cool just
motikmotik

Answer:

1. The ground state describes the lowest possible energy that an atom can have. An electron is normally in its ground state, the lowest energy state available.

2. In a metal, atoms readily lose electrons to form positive ions (cations). These ions are surrounded by delocalized electrons, which are responsible for conductivity. The solid produced is held together by electrostatic interactions between the ions and the electron cloud. These interactions are called metallic bonds. The metallic bonding model explains the physical properties of metals. Metals conduct electricity and heat very well because of their free-flowing electrons. As electrons enter one end of a piece of metal, an equal number of electrons flow outward from the other end.

3.  Physical properties are affected by the strength of intermolecular forces. Melting, boiling, and freezing points increase as intermolecular forces increase. Vapor pressure decreases as intermolecular forces increase. The physical state and properties of a particular compound depend in large part on the type of chemical bonding it displays. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound.

Explanation:

This is from 38 minutes ago. Sorry for late reply.  I really hope this helps. :)

4 0
3 years ago
Ammonia, NH3NH3 , can react with oxygen to form nitrogen gas and water. 4NH3(aq)+3O2(g)⟶2N2(g)+6H2O(l) 4NH3(aq)+3O2(g)⟶2N2(g)+6H
solmaris [256]

Answer:

36.37% is the percent yield of the reaction.

Explanation:

4NH_3(aq)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(l)

1)0.650 L nitrogen gas  , at 295 K and 1.01 bar.

Let the moles of nitrogen gas be n.

Pressure of the gas ,P=  1.01 bar = 0.9967 atm (1 bar = 0.9869 atm)

Temperature of the gas = T =  295 K

Volume of the gas = V = 0.650 L

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.9967 atm\times 0.650 L}{0.0821 atm L/mol K\times 295 K}=0.0267 mol

2) Moles of ammonia gas=\frac{2.53 g}{17 g/mol}=0.1488 mol

Moles of oxygen gas =\frac{3.53 g}{32 g/mol}=0.1101 mol

According to reaction ,3 mol of oxygen reacts with 4 mol of ammonia.

Then,0.1101 mol of oxygen will react with:

\frac{4}{3}\times 0.1101 mol=0.1468 mol of ammonia.

Hence, oxygen gas is in limiting amount and act as limiting reagent.

3) Theoretical yield of nitrogen gas :

According to reaction, 3 mol of oxygen gas gives 2 moles of nitrogen gas.

Then 0.1101 mol of oxygen will give:

\frac{2}{3}\times 0.1101 mol=0.0734 mol of nitrogen.

Theoretical yield of nitrogen gas = 0.0734 mol

Experimental yield of nitrogen as calculated in part (1) = 0.0267 mol

Percentage yield:

\frac{\text{Experiential yield}}{\text{Theoretical yield}}\times 100

Percentage yield of the reaction:

\frac{ 0.0267 mol}{0.0734 mol}\times 100=36.37\%

36.37% is the percent yield of the reaction.

3 0
3 years ago
Name at least four other gases in the atmosphere besides oxygen and nitrogen
nikitadnepr [17]
Carbon dioxide (CO2)
Argon (Ar)
Hydrogen (H)
Helium (He)
8 0
3 years ago
How can a material get a charge?
svet-max [94.6K]

Explanation:

By losing or gaining electrons from its outermost orbit

8 0
3 years ago
Read 2 more answers
A sample of 0.370 mol of a metal oxide (m2o3) weighs 55.45 g. how many grams of o are in the sample?
Wewaii [24]
0.370 mol metal oxide = 55.45 g 

<span>1 mol = 55.45/0.370 = 149.86 g </span>

<span>in 1 mol there are 3 mol O = 16 * 3 = 48 g of O </span>

<span>there is 48/149.86 * 100% O in the sample </span>

<span>the sample has 48/149.86 * 0.370 = 0.119 g O</span>
6 0
3 years ago
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