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motikmotik
3 years ago
15

Which atom has the weakest attraction for electrons in a chemical bond?(1) a boron atom (3) a fluorine atom(2) a calcium atom (4

) a nitrogen atom
Chemistry
2 answers:
BARSIC [14]3 years ago
6 0
The (2) calcium atom, because when looking at the periodic table, we see that the calcium atom is in a location where according to the periodic table, has the lower electronegativities in respect to the other three choices. We see that it also has a lower electronegativity value than the others. Electronegativity is the attraction constant for the electrons in a chemical bond. The higher the electronegativity, the higher the attraction of the electrons. Fluorine has the highest electronegativity with 4.0.
frosja888 [35]3 years ago
6 0
The calcium atom has the weakest attraction for electrons in a chemical bond
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3 years ago
According to the vsepr model the arrangement of electron pairs around nh3 and ch4 is
bazaltina [42]
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3 years ago
4. The vet instructed Manuel to give his
djverab [1.8K]

Answer:

=60 milligrams

Explanation:

12 x 5

=60 milligrams

Have a nice day!!!!!!! :-)

<u>KA</u>

3 0
2 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


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3 years ago
AICI3(s)+Ca 3N2(s)-AIN(S)+CaCl2(s)
disa [49]

Answer:

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