Based on the balanced equation, for every mole of iron (II) oxide reacted, ¹/₃ the number of moles of aluminum oxide is produced. This is because the mole ratio of FeO : Al₂O₃ is 3 : 1.
∴ the moles of Al₂O₃ produced = 0.106 mol × ¹/₃
= 0.035 mol
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