Answer:
90 C
Explanation:
Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,
I = dQ/dt
dQ = Idt
∫dQ = ∫Idt
Q = It................................ Equation 1
Where Q = amount of charge, I = current, t = time.
Given: I = 3.6 A, t = 25 s.
Substituting into equation 1,
Q = 3.6(25)
Q = 90 C.
Hence the amount of charge passing through the cross section of the conductor = 90 C
Answer:
1470 W
Explanation:
Power: This can be defined as the rate at which work is done or energy is used up. The S.I unit of power is Watt (W).
The expression for power is given as,
P = Energy/time
P = mgh/t ...................... Equation 1
Where P = power, m = mass, h = height, t = time, g = acceleration due to gravity.
Given: m = 75 kg, g =9.8 m/s², h = 1 m, t = 1 s.
Substitute into equation 1
P = (75×1×9.8)/1
P = 735 W.
From the above,
1 hp = 735 W
2 hp = (2×735) W
2 hp = 1470 W.
Hence 2 hp = 1470 W
