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Bingel [31]
3 years ago
13

A solid metal sphere of radius 3 m carries a total charge of -5.5 uc. What is the magnitude of the

Physics
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

2.9::: 5.87*10*3 N/C

8: 7.73 × 10 ^2  N/C

Explanation: https://study.com/academy/answer/a-solid-metal-sphere-of-radius-3-00-m-carries-a-total-charge-of-5-50-muc-what-is-the-magnitude-of-the-electric-field-at-each-of-the-following-distances-from-the-sphere-s-center-a-3-10-m-b-8-00-m.html

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The propeller on a boat motor is initially rotating at 8 revolutions per second. As the boat captain reduces the boat speed, the
I am Lyosha [343]

Answer: 5.77\ rps

Explanation:

Given

Initial angular velocity is \omega_i=8\ rps

rate of reduction \alpha=0.9 rev/s^2

after 17 revolution i.e. \theta =17\ rev

using \Rightarrow \omega_f^2-\omega_i^2=2\alpha\theta

Insert the values

\Rightarrow \omega_f^2=8^2-2\times (0.9)\times17\\\Rightarrow \omega_f^2=33.4\\\Rightarrow \omega_f=5.77\ rps

5 0
3 years ago
A battery-operated car uses a 12.0-V system. Find the charge the batteries must be able to move in order to accelerate the 956kg
DiKsa [7]
<h2>Answer:</h2>

1.99 x 10⁶C

<h2>Explanation:</h2>

The electrical energy (E_{E}) stored in the battery will give the car some kinetic energy (E_{K}) which will cause the car to move from rest to some other point.

i.e

E_{E} = E_{K}                 ------------------(i)

<em>But;</em>

E_{E} =  \frac{1}{2} x Q x V;            -------------------(ii)

Where;

Q = charge on the battery

V = potential difference or voltage of the battery = 12.0V

<em>Also</em>

E_{K} = (\frac{1}{2} x m x v²) - (\frac{1}{2} x m x u²)            -----------------(iii)

Where;

m = mass of the car = 956kg

v = final velocity of the car = 158m/s

u = initial velocity of the car = 0   [since the car starts from rest]

<em>Substitute equations (ii) and (iii) into equation (i) as follows;</em>

\frac{1}{2} x Q x V = (\frac{1}{2} x m x v²) - (\frac{1}{2} x m x u²)       -----------------(iv)

<em>Substitute all necessary values into equation (iv) as follows;</em>

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²) - (\frac{1}{2} x 956 x 0²)

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²) - (0)

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²)

\frac{1}{2} x Q x 12.0 = 11932792

6Q = 11932792

<em>Solve for Q;</em>

Q =  11932792 / 6

Q = 1988798.67 C

Q = 1.99 x 10⁶C

Therefore, the amount of charge the batteries must have is 1.99 x 10⁶C

8 0
4 years ago
This boy uses a force to lift a heavy rock. (He is carrying it.) What can the boy do if he wants to lift the same rock more quic
lutik1710 [3]
I nthink the  answer is c may be
5 0
3 years ago
Read 2 more answers
What is the momentum of a 0.145 kg baseball traveling at 40.0 m/s
dimulka [17.4K]
Answer: 5.8 kg m/s

Identify the given information.
m = 0.145 kg
v = 40.0 m/s

Choose which formula you should use. In this case, you are finding momentum.
p = mv, where p is momentum.

Substitute and solve.
p = 0.145 kg x 40.0 m/s
p = 5.8 kg m/s
7 0
3 years ago
If you are over-driving your headlights and you see an object ahead, you will_____. be given the right-of-way from other vehicle
SashulF [63]

Answer: not be able to stop in time to miss the object

Explanation:

The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.

When this occurs, it will be impossible for the vehicle to stop moving in time to avoid an object viewed by the driver in the range of his headlights.

This is a <u>dangerous driving practice</u> and can be avoided by driving at <u>reduced speeds</u>.

5 0
4 years ago
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