Suppose that a car starts from rest at t = 0. The car moves with an acceleration of 1.5 m/s2. How far will the car travel in 3.0
1 answer:
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Answer:
The compression of the spring is 24.6 cm
Explanation:
magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C
magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C
distance between the two charges, r = 3 cm = 0.03 m
spring constant, k = 14 N/m
The attractive force between the two charges is calculated using Coulomb's law;
The extension of the spring is calculated as follows;
F = kx
x = F/k
x = 3.45 / 14
x = 0.246 m
x = 24.6 cm
The compression of the spring is 24.6 cm
A) Net force in component form:
B) Magnitude of the net force: 316.2, direction:
Explanation:
A)
The three forces given in this problem are:
The three forces are given in component form, where the components with unit vector i is the component along the x-direction, while the components with unit vector j is the component along the y-direction.
In order to find the net force in component form, we just need to add the components of the three forces along each direction. Therefore:
- Along the x-direction:
- Along the y-direction:
So, the net force in component form is
B)
The magnitude of a vector F is given by Pythagorean's theorem:
where in this problem,
is the x-component
is the y-component
Substituting,
The direction instead is given by
where the negative sign means the direction is below the positive x-axis.
Learn more about vector addition:
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