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3 years ago

10

write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, projvu u=(-9,3), v=(-9

,3)

1 answer:

LuckyWell [14K]3 years ago

5 0

Answer:

u = v

Step-by-step explanation:

Vector u appears to be the same as v, so its decomposition is simply ...

u = projvu = v

__

There is no orthogonal component.

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On her birthday, Sonia distributed chocolates in an orphanage. She gave 5 chocolates to each child and 20 chocolates to adults.

qwelly [4]

Answer with explanation:

Total number of Children = x Children

Total number of chocolates distributed = y Chocolates

If there are x children, then total number of chocolate got by children= 5 x Chocolate

Number of chocolate got by Adults= 20

Let total number of adults be z.

Expressing the statement in terms of Equation

y = 5 x + 20 z

$z=\frac{y-5 x}{20}$

⇒Number of Adults =z

$=\frac{y-5 x}{20}$

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3 years ago

The tens digit of a two-digit number is twice the units digit. If the digits are reversed, the new number is 36 less than the or

Ludmilka [50]

Try this solution:
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
$\left \{ {{x=2y} \atop {10x+y-(10y+x)=36}} \right. \ =\ \textgreater \ \ \left \{ {{x=8} \atop {y=4}} \right.$
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There was inertia in the soccer ball from your foot, I can’t really tell if this is a math question or a science question but basically the soccer ball was in motion and now isn’t and your foot was what provided that motion

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-Dominant- [34]

Hi!

I would approach this question by first looking at where the parallelogram is located, by graphing the image. I did so and drew a rough image on Paint (See attached image)

To get the part where the diagonals intersect, I would find the midpoint of the line between points (1, 3) and (5,-9) (or the other pair). The reason is a parallelogram's diagonals always bisect each other, meaning the point they intersect is always the middle of the two diagonals.

Therefore, you can find the midpoint of a diagonal, between (1, 3) and (5, -9). The midpoint theorem is ( $\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}$ .

Take the points (1, 3) and (5, -9), and fill them in.

$(\frac{1 + 5}{2} , \frac{3 - 9}{2})$

Then solve.

$(\frac{6}{2}, \frac{-6}{2})$

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If you'd like to check the other midpoint:

Take the points, (8, 3) and (-2, -9)

$(\frac{8 - 2}{2}, \frac{3 - 9}{2})$

Then solve.

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They're the same, so that answer is correct.

Hope this helps!

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