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satela [25.4K]
3 years ago
8

our bedroom ceiling is 10 feet high and is 2/3 as high as the living room ceiling. Write and solve an equation to find the heigh

t h of the living room ceiling.
Mathematics
1 answer:
Doss [256]3 years ago
8 0
I know this probably isn't helpful to you, but the answer is 15. I suck at showing my work. So I really can't help you there. Sorry I couldn't be more help.

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How many variable terms are in the expression 3x^y + 5x^ - 4y + z + 9?
Bess [88]
The number of variables in the problem is 3
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What is the square root of 36/196<br> √36/169
Andrei [34K]

Answer:

<em>The square root of 36/196 is </em><em>3</em><em>/</em><em>7</em><em>.</em>

<em>The </em><em>square</em><em> root</em><em> of</em><em> </em><em>3</em><em>6</em><em>/</em><em>1</em><em>6</em><em>9</em><em> </em><em> </em><em>is </em><em> </em><em>6</em><em>/</em><em>1</em><em>3</em><em>.</em>

5 0
2 years ago
Read 2 more answers
Please help me! I will give you Brainlist if you get it right!​
Sedaia [141]

Answer:

B

Step-by-step explanation:

find the area of the rectangle and then find the area of the semi circle, then add the 2 together

6 0
3 years ago
Will award brainlyist! 15 pts!<br> Find the perimeter of the window to the nearest hundredth.
yawa3891 [41]

Answer:

7.71

Step-by-step explanation:

The diameter is 3, so the arc length is 180/360 * 3pi or 3pi/2. Now you add the 3 in the base, so it is 3pi/2 + 3 or approximately 7.71 (I used a calculator for that).

3 0
3 years ago
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
3 years ago
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